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Pavlova-9 [17]
3 years ago
8

PLEASE HELP ASAP GEOMETRY ​

Mathematics
1 answer:
deff fn [24]3 years ago
6 0
The reflections are on the 3rd and 4th quadrant in the inserted picture.

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How do you Simplify 6(-3 + 2 - 5x)
STALIN [3.7K]

Answer:

-6 -30x

Step-by-step explanation:

6(-3 + 2 - 5x)

Combine like terms inside the parentheses

6( -1-5x)

Distribute the 6 to all terms inside the parentheses

-6 -30x

7 0
4 years ago
How do i find a vertex of a parabola
DanielleElmas [232]

Answer:

The standard form of a parabola is

y=ax2+ +bx+c, where a≠0.

To find the vertex, you need to find the x- and y-coordinates.

7 0
3 years ago
A sports writer wished to see if a football filled with helium travels farther, on average, than a football filled with air. To
Vesnalui [34]

Answer:

(-3.07, 11.07)

Step-by-step explanation:

Given that a sports writer wished to see if a football filled with helium travels farther, on average, than a football filled with air. To test this, the writer used eighteen adult male volunteers. These volunteers were randomly divided into two groups of nine subjects each.

Group   Group One     Group Two  

Mean 300.00 296.00

SD 8.00 6.00

SEM 2.67 2.00

N 9     9    

The mean of Group One minus Group Two equals 4.00

 

standard error of difference = 3.333

   df = 16

t = 1.2000

Margin of error = 3.3333* t critical = 3.3333*2.121

 95% confidence interval of this difference: From -3.07 to 11.07

7 0
3 years ago
Write 16 exponentially two different ways
Bogdan [553]

Answer:

2^4 or 4^2

Step-by-step explanation:

2^4= 2x2x2x2=16

4^2= 4x4=16

5 0
3 years ago
A train travels a distance of 60 km at uniform speed. If the speed of the train was reduced by 10 kmh-1, the time taken to trave
tester [92]

Answer:

<u>Initial</u><u> </u><u>speed</u><u> </u><u>is</u><u> </u><u>3</u><u>2</u><u> </u><u>m</u><u>/</u><u>s</u>

At uniform speed, acceleration is 0, (a = 0).

When speed reduced, (v - u) = 2.78 ms-¹, t = 1800 sec, s = 60 ,000 metres.

From first equation of motion:

{ \boxed{ \bf{v = u + at}}} \\  { \tt{(v - u) = at}}

substitute:

{ \tt{2.78 = (a \times 1800)}} \\ { \tt{acceleration = 0.0015 \:  {ms}^{ - 2} }}

from second equation of motion:

{ \boxed{ \bf{s = ut +  \frac{1}{2} a {t}^{2} }}}

substitute:

{ \tt{60000 = 1800u + ( \frac{1}{2} \times 0.0015 \times  {1800}^{2})  }} \\ { \tt{1800u = 57570}} \\ { \tt{u = 32 \: m {s}^{ - 1} }}

5 0
3 years ago
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