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olchik [2.2K]
2 years ago
12

An amusement park contend the tickets sales over the weekend and found that 51,368 tickets were sold what was the number of tick

ets sold rounded to the nearest hundred
Mathematics
1 answer:
GuDViN [60]2 years ago
3 0
Hi there!

When you round something, is usually the number under 4 (rounded down) or 5 and up (rounded up). This can be done to tens, hundreds, thousands, etc.

Here, look at the hundreths place. The number is under 4, so we round down, right? Not quite. The full number is 368. The number is closer to 400 than 300. So, we round up to 400.

The number you would write is 51,400.

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one! :)
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Solve the absolute value inequality |x+9| > 3
Studentka2010 [4]

Answer:

x>−6,x<−12

Step-by-step explanation:

Break down the problem into these 2 equations.

x+9>3x+9>3

-(x+9)>3−(x+9)>3

Solve the 1st equation: x+9>3x+9>3.

x>-6x>−6

3 Solve the 2nd equation: -(x+9)>3−(x+9)>3.

x<-12x<−12

Collect all solutions.

x>-6,x<-12x>−6,x<−12

8 0
3 years ago
What is the period of the graph of y = 5 sin (pi x) + 3?
Natasha2012 [34]

Equate whats inside (arguments) \sin with base period of sine function 2\pi and solve for x to get period,

\pi x=2\pi\implies x=2

So the period of the graph of the given function is precisely 2.

Hope this helps :)

7 0
3 years ago
5 times what thousandths equals 0.045?
notka56 [123]
.009 is the answer to this equation
7 0
3 years ago
Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x &gt; 0 [−4, 5]The f
quester [9]

Answer:

It is continuous since \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)

Step-by-step explanation:

We are given that the function is defined as follows f(x) = 9-x, x\leq 0 and f(x) = 9+12x, x>0 and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity)  x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all \mathbb{R}. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x) (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9, so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

5 0
3 years ago
Read 2 more answers
Find the fifth term of the binomial expansion.<br> (x2+y5) ^8
OlgaM077 [116]

Answer:

The fifth term of the binomial expansion

T_{5} = 70 x^{8} y^{20}

Step-by-step explanation:

<u><em>Step:1</em></u>

Given that the binomial expansion

     ( x² + y⁵ )⁸

we know that

T_{r+1} = n_{C_{r} } a^{r} x^{n-r} ...(i)

<u><em>Step:2</em></u>

put r = 4  

T_{4+1} = 8_{c_{4} } (x^{2} )^{4} (y^{5} )^{8-4}

T_{5} = 70 x^{8} y^{20}

<u><em>Final answer:</em></u>-

The fifth term of the binomial expansion

T_{5} = 70 x^{8} y^{20}

6 0
3 years ago
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