Explanation: Given: Clayton bikes 3/8<span> of </span>14.5 miles<span>. </span>38⋅14.5<span>1=43.58=5.4375 </span>miles biked<span>. Left to </span>bike<span> to </span>beach<span>: 14.4−5.4375=9.0625 </span>miles<span>. OR. </span>38 biked<span>, means 58 left to </span>bike: 58⋅14.5<span>1=72.58=9.0625 </span>miles<span>. Was this helpful? </span>
Answer:
B: 8 7/8 Lbs
Step-by-step explanation:
answer = 
step 1 find a common denominator
common denominator - 8
* apply *

now we have

step 2 make each fraction a improper fraction
We can do this my multiplying the big number by the denominator and adding that to the numerator.

now we have

Now we can subtract
remember when subtracting fractions you only subtract the numerators. ( so we keep the denominator as 8 )
so 121 - 28 - 22 = 71
so the answer is 
finally we want to change the answer back into a mixed fraction
To do this we divided 71 and 8
8 can go into 71 8 times
8 * 8 = 64
71 - 64 = 7
We're left with 
Answer:
30
Step-by-step explanation:
First, add 3 and 7
3 + 7 =10
The multiply by 3
10*3= 30
Hope this helps!
Answer:
(i) A truth table shows how the truth or falsity of a compound statement depends on the truth or falsity of the simple statements from which it's constructed.
Since A ∧ B (the symbol ∧ means A and B) is true only when both A and B are true, its negation A NAND B is true as long as one of A or B is false.
Since A ∨ B (the symbol ∨ means A or B) is true when one of A or B is true, its negation A NOR B is only true when both A and B are false.
Below are the truth tables for NAND and NOR connectives.
(ii) To show that (A NAND B)∨(A NOR B) is equivalent to (A NAND B) we build the truth table.
Since the last column (A NAND B)∨(A NOR B) is equal to (A NAND B) it follows that the statements are equivalent.
(iii) To show that (A NAND B)∧(A NOR B) is equivalent to (A NOR B) we build the truth table.
Since the last column (A NAND B)∧(A NOR B) is equal to (A NOR B) it follows that the statements are equivalent.
<span>The two checkpoints are 4,920 ft. apart from each other. The total distance of the race is 15,840 ft. If checkpoint C half the distance between checkpoint B and the end of the race, the distance between Checkpoint B and the end of the race is 9,840 ft. Half of that distance is 4,920 ft.</span>