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lora16 [44]
3 years ago
12

What is the answer to 46×10

Mathematics
1 answer:
Lyrx [107]3 years ago
7 0

Answer:4600

Step-by-step explanation:

46 multiplied 100 times, most the time you just add the last two zeros from 100 onto 46

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both the red and blue line segments stretch from the center of the circle to a point on the circle. the legth of the blue line s
stiv31 [10]

Answer:

7.5

Step-by-step explanation:

It is longer than 5, so cross 2.5 and 5 out, 10 is too big, so 7.5 is the correct answer

4 0
3 years ago
Among a sample of 55 male soldiers the average shower time was found to be 2.95 minutes and the population standard deviation is
Oksanka [162]

Answer: -3.0593

Step-by-step explanation:

The test statistic for the difference between two population mean (when population standard deviations \sigma_1\ \&\ \sigma_2  are known ) is given by :-

z=\dfrac{\overline{x}_1-\overline{x}_2}{\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}}

where ,

n_1\ \&\ n_2 = Sample sizes taken from two  populations 1 and 2.

\overline{x}_1-\overline{x}_2 = Difference between two Sample mean.

\sigma_1\ \&\ \sigma_2 = Standard deviations of populations 1 and 2.

As per given , we have

n_1=55\ \&\ n_2=58

\overline{x}_1=2.95\ \&\ \overline{x}_2=3.3

\sigma_1=0.65\ \&\ \sigma_2=0.56

We assume that the data follows a normal distribution.

Then, the test statistic will be :-

z=\dfrac{2.95-3.3}{\sqrt{\dfrac{(0.65)^2}{55}+\dfrac{(0.56)^2}{58}}}\\\\=\dfrac{-0.35}{\sqrt{0.0130887}}\\\\=\dfrac{-0.35}{0.1144059}=3.05928278174\approx-3.0593  

Hence, the test statistic= -3.0593

5 0
3 years ago
The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func
katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle (\frac{1}{3},\frac{1}4).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A(\frac{1}{3},\frac{1}4)

Let O be the origin i.e. (0,0)

Point B will be (\frac{1}{3},0)

Now, let us consider the right angled triangle \triangle OBA:

Sides:

Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}

Using Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}

sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}

\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}

cos\angle AOB = \dfrac{Base}{Hypotenuse}

\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}

tan\angle AOB = \dfrac{Perpendicular}{Base}

\Rightarrow tan\angle AOB = \dfrac{3}{4}

cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}

\Rightarrow cosec\angle AOB = \dfrac{5}{3}

sec\angle AOB = \dfrac{Hypotenuse}{Base}

\Rightarrow sec\angle AOB = \dfrac{5}{4}

cot\angle AOB = \dfrac{Base}{Perpendicular}

\Rightarrow cot\angle AOB = \dfrac{4}{3}

3 0
3 years ago
Is this answer correct ?
Sever21 [200]
Yes you are correct!
6 0
3 years ago
Read 2 more answers
What is 5,000 in scientific notation?
eimsori [14]
5.0x103

Bolded=exponent
4 0
3 years ago
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