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3 years ago

HELPPP ASAP What is the value of x in this equation 1/2x - 9 = 36

Mathematics

2 answers:

sleet_krkn [62]3 years ago

8 0

Answer:

Step-by-step explanation:

Ber [7]3 years ago

3 0

1/2x=36+9
1/2x=45
1=45*2x
1=90x
X=1/90

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write the standard form of the equation of the circle for which the endpoints of a diameter are (0,0) and (4,-6)

Elenna [48]

Given:

The endpoints of a diameter are (0,0) and (4,-6).

To find:

The equation of the circle.

Solution:

The endpoints of a diameter are (0,0) and (4,-6). So, the length of the diameter is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-6-0)^2+(4-0)^2}$

$d=\sqrt{36+16}$

$d=\sqrt{52}$

$d=2\sqrt{13}$

Now, radius is half of the diameter.

$r=\dfrac{2\sqrt{13}}{2}$

$r=\sqrt{13}$

Center of the circle is the midpoint of the endpoints of a diameter.

$Center=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Center=\left(\dfrac{0+4}{2},\dfrac{0+(-6)}{2}\right)$

$Center=\left(\dfrac{4}{2},\dfrac{-6}{2}\right)$

$Center=\left(2,-3\right)$

Standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$

where, (h,k) is center and r is radius.

The center of the circle is (2,-3) and radius is $\sqrt{13}$ . So,

$(x-2)^2+(y-(-3))^2=(\sqrt{13})^2$

$(x-2)^2+(y+3)^2=13$

Therefore, the standard form of the circle is $(x-2)^2+(y+3)^2=13$ .

5 0

3 years ago

PLEASE HELP ME!!!!! I HAVE TRIED THIS QUESTION 5X ALREADY AND I STILL CANNOT GET THE RIGHT ANSWER!!! I KNOW THE ANSWER BUT I HAV

kirill [66]

Answer:

x = 3 and y = 2

(3,2)

Step-by-step explanation:

first equation (LCM = 3 x 4 x 5 = 60)

(x+2)/5 - (9-x)/3 = (y - 6)/4

12(x+2) - 20(9-x) = 15(y - 6)

12x + 24 - 180 + 20x = 15y - 90

32x - 15y = -90 - 24 + 180

32x - 15y = 66

second equation:

8(x + 2) - (2x + y) = 2(x + 13)

8x + 16 - 2x - y = 2x + 26

6x - y + 16 = 2x + 26

4x - y = 10

Now you have 2 equations:

4x - y = 10 ---> y = 4x - 10

32x - 15y = 66

Substitute y = 4x - 10 into 32x - 15y = 66

32x - 15(4x - 10) = 66

32x - 60x + 150 = 66

-28x = -84

x = 3

y = 4(3) - 10

y = 12 - 10

y = 2

Solutions: x = 3 and y = 2

6 0

3 years ago

How to solve the inequality 1/5 ≤ x/15?

MAXImum [283]

Answer:

3 <_ x

Step-by-step explanation:

multiply both sides by 15

1/5 * 15 <_ x

15/5 <_ x

3 <_ x

8 0

3 years ago

How do I solve 4(5(6))<br><br> This is a hypothetical question

SSSSS [86.1K]

PEMDAS states that the value in the parenthesis should be evaluated first:
4(5*6)
4(30)
After just multiply the value in the parenthesis by the number outside of the parenthesis:
120

6 0

3 years ago

Read 2 more answers

Which ordered pairs are solutions to the inequality 2x + y > 8 ? Choose all answers that are correct.

gtnhenbr [62]

Hi again!

2x + y > 8

The correct answer is option D
-------------------------------------------

Honestly I don't think we can solve the equation to find the answer. What we can do is to find the boundary line. (I think you know what that is) After that, shading the appropriate area.

y > -2x + 8

Again, credit to my beautiful graphing calculator. Here is how it looks like.

6 0

3 years ago