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Sav [38]
3 years ago
9

Algebra 1 help please

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
3 0
Short leg = ?
Long leg = 1/2x + 11
Hypotenuse = 2x + 1

For this you'd need to use the Pythagorean Theorem to find the short leg.

Pythagorean Theorem - a^2 + b^2 = c^2
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What is the missing pattern 7, 11, 2, 18, -7
Alexxx [7]

The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}, equivalent to the <em>recurrence</em> formula a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}.

<h3>What is the missing element in a sequence?</h3>

A sequence is a set of elements which observes at least a <em>defined</em> rule. In this question we see a sequence which follows this rule:

n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}      (1)

Now we prove that given expression contains the pattern:

n = 0

7

n = 1

7 + (- 1)² · 2² = 7 + 4 = 11

n = 2

7 + (- 1)² · 2² + (- 1)³ · 3² = 11 - 9 = 2

n = 3

7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² = 2 + 16 = 18

n = 4

7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² + (- 1)⁵ · 5² = 18 - 25 = - 7

The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}, equivalent to the <em>recurrence</em> formula a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}.

To learn more on patterns: brainly.com/question/23136125

#SPJ1

8 0
2 years ago
Help pls will mark branliest !
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Answer:

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Answer: The answer is 1/21

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ehidna [41]
The term in that equation is 3x 7x and -9 hope this helps
7 0
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