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lianna [129]
3 years ago
7

For f(x)=2x^2+1 and g(x)= x^2-7, find (f+g)(x)

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

f(x)=2x^2+1;\ g(x)=x^2-7\\\\(f+g)(x)=f(x)+g(x)=(2x^2+1)+(x^2-7)\\\\=2x^2+1+x^2-7=(2x^2+x^2)+(1-7)\\\\Answer:\ \boxed{C.\ 3x^2-6}

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Only 7 people can play and 1 card will remain

Step-by-step explanation:

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2 years ago
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The graph shows the number of flowers that can be pollinated as the number of bees increase. What is the unit rate?
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5 0
3 years ago
What is the answer to this question it doesn't state the answer so can you please tell me the answer
DiKsa [7]
I DONT KNOW JUST STRAT WITH THE BEGGINIG OF THE SENTENCE 

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3 years ago
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The LCM of two numbers is 60. Their GCf is 6 and their difference is 18. What are the two numbers?
Aliun [14]
LCM(x,y)=60\\
GCF(x,y)=6\\
x-y=18\\\\
LCM(x,y)=\dfrac{|x\cdot y|}{GCD(x,y)}\\
60=\dfrac{|x\cdot y|}{6}\\
|x\cdot y|=360\\\\\\
|x\cdot y|=360\\
x-y=18\\\\
|x\cdot y|=360\\
x=18+y\\\\
|(18+y)\cdot y|=360\\
|18y+y^2|=360\\
18y+y^2=360 \vee 18y+y^2=-360\\
y^2+18y+81=441 \vee y^2+18y+81=-279\\
(y+9)^2=441 \vee (y+9)^2=-279\\
y+9=\sqrt{441} \vee y+9=-\sqrt{441}\\
y=21-9 \vee y=-21-9\\
y=12 \vee y=-30\\\\
x-12=18 \vee x-(-30)=18\\
x=30 \vee x=-12\\\\
\boxed{x=30, y=12 \vee x=-12, y=-30}
4 0
3 years ago
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Please help if you can :)
crimeas [40]

The graph is Parabola or Graph of Quadratic Function.

The graph has minimum value, not maximum. So ( A ) is not correct for maximum part.

B is not correct for exponential part.

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So the answer is D.

7 0
3 years ago
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