For f(x)=2x^2+1 and g(x)= x^2-7, find (f+g)(x)

1 answer:

4 0

$f(x)=2x^2+1;\ g(x)=x^2-7\\\\(f+g)(x)=f(x)+g(x)=(2x^2+1)+(x^2-7)\\\\=2x^2+1+x^2-7=(2x^2+x^2)+(1-7)\\\\Answer:\ \boxed{C.\ 3x^2-6}$

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