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harkovskaia [24]
3 years ago
8

Anyone know dis, my brain is a cumwad rn

Mathematics
2 answers:
Vlad1618 [11]3 years ago
8 0

Given Function : f(x) = x² - 9

We can notice that : The function f(x) is zero for only two values of x and they are -3 and 3

⇒   f(-3) = (-3)² - 9 = (9 - 9) = 0

⇒   f(3) = (3² - 9) = (9 - 9) = 0

⇒   The ordered pairs of the zeroes : (-3 , 0) ; (3 , 0)

Galina-37 [17]3 years ago
4 0

ans (-3,0):(3,0)

I'm not sure but hope this helps

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elena-s [515]

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Step-by-step explanation:

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f(x)=\frac{(x+3)(x+9)}{(x+1)(x+3)} and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.

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