Anyone know dis, my brain is a cumwad rn

Mathematics

2 answers:

Vlad1618 [11]3 years ago

8 0

Given Function : f(x) = x² - 9

We can notice that : The function f(x) is zero for only two values of x and they are -3 and 3

⇒ f(-3) = (-3)² - 9 = (9 - 9) = 0

⇒ f(3) = (3² - 9) = (9 - 9) = 0

⇒ The ordered pairs of the zeroes : (-3 , 0) ; (3 , 0)

Galina-37 [17]3 years ago

4 0

ans (-3,0):(3,0)

I'm not sure but hope this helps

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Gerald graphs the function f(x) = (x – 3)2 – 1. Which statements are true about the graph? Check all that apply. The domain is {

katrin2010 [14]

Hey! Statement 1 is false because the domain of f is all real numbers since the function is quadratic.

Statement 2 is true.

Statement 3 is true because when we graph f, it is a parabola opening upwards with vertex (3, -1). Since it is opening upward, then the value of x from -∞ to 3 is decreasing while increasing from 3 to ∞.

Statement 4 is false because we just stated above that f is decreasing from -∞ to 3. Hence, f is also decreasing from -1 to 3. Hence, f is not increasing from -1 to ∞.

Statement 5 is false because the axis of symmetry is x = 3.

Statement 6 is true.
Hope this helps! :)

8 0

3 years ago

Read 2 more answers

You have a biased coin for which p(h)=pp(h)=p. you toss the coin 2020 times. what is the probability that you observe 88 heads a

Nat2105 [25]

The question describes a binomial probability with p(h) = p, then p(t) = 1 - p and number of trials (n) = 20

The probability of a binomial distribution is given by

$P(x)=\, ^nC_xp^x(1-p)^{n-x}$

Part A:

The probability of observing 8 heads and 12 tails is given by:

$P(8)=\, ^{20}C_8p^8(1-p)^{20-8}=\, ^{20}C_8p^8(1-p)^{12}$

Part B:

You observe more than 8 heads and more than 8 tails, when you observe 9 heads and 11 tails, 10 heads and 10 tails, and 11 heads and 9 tails.

Therefore, the probability of observing more than 8 heads and more than 8 tails is given by:

$P(9)+P(10)+P(11) \\ \\ =\, ^{20}C_9p^9(1-p)^{20-9}+\, ^{20}C_{10}p^{10}(1-p)^{20-10}+\, ^{20}C_{11}p^{11}(1-p)^{20-11} \\ \\ =\, ^{20}C_9p^9(1-p)^{11}+\, ^{20}C_{10}p^{10}(1-p)^{10}+\, ^{20}C_{11}p^{11}(1-p)^{9}$