7. y = 1, AB = 1, BD = 10 and AD = 11
8. x = 5, AB = 20 and BC = 20
9. x= 5 and AB = 33
10. No, because AC = 12.5 while AB + BC = 20 (they should equal the same and they don't.)
1.)11x^2-3x
2.)8x+1-x^2
3.)-x^2-x+8
4.)-2y+10-x^2
Answer:
- 0, 3, 8, 15, 24
- y = x² + 2x
Step-by-step explanation:
<u>The pattern is</u>
- Step 1 ⇒ 1*3 = 3
- Step 2 ⇒ 2*4 = 8
- Step 3 ⇒ 3*5 = 15
<u>Next step would be</u>
<u>Step zero would be</u>
<u>The equation</u>
Answer:
a)
b)
c) n=62
d) n=138
Step-by-step explanation:
Note: "Each chip contains n transistors"
a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:
b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.
We can calculate this as a binomial distribution problem, with n=9 and k≥8:
c)
This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.
d) If the memoty module tolerates 2 defective chips:
We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.
So x + y = 45, and 4x + 5y = 195. Get y by itself. Subtract x from both sides in the first equation to get y = 45 -x, and subtract 4x from the second equation to get 5y = 195 - 4x. Divide by 5 to both sides to get y = 39 - 4/5x. 39 - 4/5x = 45 - x. Add x to both sides to get 39 - 1/5x = 45. Subtract 39 from both sides to get -1/5x = 6. Divide by -1/5 to get x = -30, or 30. In the first equation, do 30 + y = 45. Subtract 30 from both sides to get y = 15. Check. 4(30) + 15(5) = 195, or 120 + 75 = 195.