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Alex Ar [27]
3 years ago
8

Jimmy gets a discount of 35% for a pair of sneakers with an original price of $70. He also gets a discount of 25% on a shirt wit

h an original price of $30. How much money does Jimmy save in all?
Mathematics
2 answers:
Tanya [424]3 years ago
8 0
First find the total without using the dicounts. then do 70×.35 which is 35% as a decimal. your answer is the dicounts but that is how much you are taking off. .35×70= 24.5 then you would do 70-24.5=45.5 then do the same for the other amount. add these two amounts together. ( 30×.25=7.5 30-7.5= 22.5) 45.5+22.5= 68 then do your first answer - 68 and that is how much is saved
ziro4ka [17]3 years ago
4 0
Jimmy saves $24.50 on the sneakers & $7.50 on the shirt. A total savings of $32.00.
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notka56 [123]

Answer:

8) 10°

9) X can not be determined.

10) 10°

11) 12 units.

Step-by-step explanation:

8) The three sides of the given triangle are equal. Hence, the triangle is an equilateral triangle, hence each angle will be 60°.

So, 6x = 60°  

⇒ x = 10°.

9) The three angles of the given triangle are equal. Hence, the triangle is an equilateral triangle, hence each side will be equal.

So, 6x - 5 = 6x

So, x can not be determined from this equation.

10) Δ KLM is equilateral, so, KN will bisect ∠ MKL. So, ∠ NKL = 30°

Hence, 3x = 30°

⇒ x = 10°

11) In Δ XYZ, XZ = XY , so, ∠ Z = ∠ Y.

Again, ∠ X is given to be 60°.

Therefore, each angle is 60°.

So, the triangle XYZ is equilateral, and each side will be equal.

So, 3x + 8 = 4x - 4

⇒ x = 12 units. (Answer)

3 0
3 years ago
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
Simplify 3(2f+6)+7<br><br><br><br><br><br><br><br>thanks
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{Expand} 3(2f+6): 6f+18

6f+18+7

18+7=25

= 6f+25

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erastova [34]

Answer:

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Answer:

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