Answer:
He showed that f(n) ÷ f(n - 1) was a constant ratio.
Given that Jake has proved that a function f(x) is a geometric sequence.
GEOMETRIC SEQUENCE: A geometric sequence is a sequence of numbers where each term is found by multiplying the preceding term by a constant called the common ratio, r.
So, in Jame's proof, he showed that each term is multiplied by a constant to get the next term.
That is, if 'c' is the constant that was used in the proof, then we must have
This implies that
Therefore, he showed that f(n) ÷ f(n - 1) was a constant ratio.
Answer:
neither, since the gradients are not the same, as well as the c value
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
Plot the solution sets to both inequalities.
1. For the inequality 
First, plot the dotted line 
(dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.
so the origin does not belong to the needed part. Shade the part, which does not include origin.
2. For the inequality 
First, plot the dotted line 
(dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.
so the origin does not belong to the needed part. Shade the part, which does not include origin.
3. Find the common region of these two shaded parts - this is the solution to the system of two inequalities.
Answer:
Step-by-step explanation:
Answer:
The net forces exerted on the horse and cart are not the same, so they are not balanced forces.
Step-by-step explanation:
Please see the Newton's 2nd Law which states that an object accelerates if there is a net or unbalanced force on it. In this scenario there is just one force exerted on the wagon i.e: the force that the horse exerts on it. The wagon accelerates because the horse pulls on it. And the amount of acceleration equals the net force on the wagon divided by its mass.
As there are two forces the push and pull the horse; the wagon pulls the horse backwards, and the ground pushes the horse forward. The net force is determined by the relative sizes of these two forces.
If the ground pushes harder on the horse than the wagon pulls, there is a net force in the forward direction, and the horse accelerates forward, and if the wagon pulls harder on the horse than the ground pushes, there is a net force in the backward direction, and the horse accelerates backward.
If the force that the wagon exerts on the horse is the same size as the force that the ground exerts, the net force on the horse is zero, and the horse does not accelerate.
