Answer:
A.Both of the students did the problem correctly.
Step-by-step explanation:
B. Nikki multiplied the fraction(8/3) to the items in the parentheses. Then multiplied each side with 3. Jon did the opposite. He first removed the fraction by multiplying each side by 3. Then he multiplied 2 to the items in the paranthesis.
C. I prefer Jon's method. Fractions can be tricky. I prefer to remove them as soon as possible. This time the items in the paranthesis had whole numbers. But had any of them been a fraction too, the problem would have gotten a lot more tricky and it would very easy to make a mistake or miscalculate something.
<span>The
associative rule is a rule about when it's safe to move parentheses
around. You can remember that because the parentheses determine which
expressions you have to do first--which numbers can associate with each
other. It looks like this:
For addition: (a + b) + c = a + (b + c)
For multiplication: (ab)c = a(bc)
The commutative property is about which operations you can do backward
and forward. You can remember this by thinking of people commuting to
work: they go to work every morning, then they repeat the same operation
backward when they commute home. It looks like this:
For addition: a + b = b + a
For multiplication: ab = ba
Finally, the distributive property tells you what happens when you
distribute one operation against another kind in parentheses. It looks
like this:
a * (b + c) = ab + ac
In other words, the a is "distributed" over the b and c.
Of course, you can make these work together:
a * (b + (c + d))
= a * ((b + c) + d) (by the associative property)
= a * (d + (b + c)) (by the commutative property)
= ad + a (b + c) (by the distributive property)
= ad + ab + ac (by the distributive property again).
Hope this helps. </span>
Answer:
No
Step-by-step explanation:
-5*1+6*5=30 as the value doesn't support the equation
Answer:
15ft
Step-by-step explanation:
you have to add 11 and 4 to get 15
Answer:
Step-by-step explanation:
Alice and Bill are planning to have three children
We have to find the probability that all three of their children will be girl.
Sample space =S={BBB,BBG,BGB,GBB,GGG,GBG,GGB,BGG}
Total =8
Number of cases in which all three children are girls={GGG}
Probability,P(E)=
Using the formula
Then , the probability that all three of their children will be girls=
