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Hitman42 [59]
2 years ago
14

The Canadian government would like to test the hypothesis that the standard deviation for the hourly wage for men is equal to th

e standard deviation for the hourly wage for women. The following data summarizes the sample statistics for hourly wages for men and women.
Men Women
Sample mean $25.40 $21.20
Sample size 20 18
Sample standard deviation $6.20 $5.90

If Population 1 is defined as men and Population 2 is defined as women, and using α = 0.025, which one of the following statements is true?

a) Because the p-value is less than α, the Canadian government cannot conclude that the average hourly wage for men is more than $2.00 higher than the average hourly wage for women.
b) Because the p-value is less than α, the Canadian government can conclude that the average hourly wage for men is more than $2.00 higher than the average hourly wage for women.
c) Because the p-value is greater than α, the Canadian government can conclude that the average hourly wage for men is more than $2.00 higher than the average hourly wage for women.
d) Because the p-value is greater than α, the Canadian government cannot conclude that the average hourly wage for men is more than $2.00 higher than the average hourly wage for women.

Mathematics
1 answer:
Sphinxa [80]2 years ago
4 0

Answer:

Because the p-value is greater than α, the Canadian government can conclude that the average hourly wage for men is more than $2.00 higher than the average hourly wage for women.

Step-by-step explanation:

See attached picture.

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A concert cleanup crew has 6 workers and one cleanup kit.
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Answer:

Option (D)

Step-by-step explanation:

At every 6 crew workers number of clean up kits required = 1

Therefore, for 1 crew worker number of kits required = \frac{1}{6}

And number of kits required for w workers = \frac{w}{6} = w ÷ 6

If w = 54

Number of kits required = \frac{54}{6}=9

If w = 60

Number of kits required = \frac{60}{6}=10

If w = 66

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6 0
3 years ago
Work out the size of one of the exterior angles
hodyreva [135]

<u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>

⠀

  • A polygon with 10 sides ( Decagon )

⠀

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>

⠀

  • The value of one of the exterior angles

⠀

<u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

\qquad \diamond \:  \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \:  \star

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<u>Solution</u><u> </u><u>:</u><u>-</u>

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Putting the given values, we get,

⠀

\sf \dashrightarrow Exterior ~angle =  \dfrac{360  ^\circ}{10} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \frac{36 \cancel{0}^\circ}{ \cancel{10}} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\  \\

Thus, the value of the exterior angles of a Decagon is 36°.

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\underline{ \rule{227pt}{2pt}} \\  \\

8 0
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Answer:

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Step-by-step explanation:

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this point will lie in third coordinate

as  third coordinate has points

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Answer:

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