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Fofino [41]
3 years ago
14

The top speed of a coyote is 43 miles per hour. find approximate spee in kilometer per minute

Mathematics
1 answer:
yuradex [85]3 years ago
4 0
43m/hr * (1 hr / 60 min) * (.6 km / 1 m) = 43*.6/60 = .43 miles per minute
You might be interested in
Find the equation of a line that goes through the points (8, -9) and (-4, 15).
Natasha_Volkova [10]

Answer:

y = - 2x + 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (8, - 9) and (x₂, y₂ ) = (- 4, 15)

m = \frac{15+9}{-4-8} = \frac{24}{-12} = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (8, - 9), then

- 9 = - 16 + c ⇒ c = - 9 + 16 = 7

y = - 2x + 7 ← equation of line

3 0
3 years ago
Find the value of pq - r/4 when p= -8 and q= -3 and r= 68
andrey2020 [161]

Answer:

7

Step-by-step explanation:

pq - r/4

(-8)(-3) - 68/4

-8 x -3 = 24 (2 negatives equal a positive)

24 - 68/4

68/4 = 17

24-17 = 7

6 0
4 years ago
1. If two nonvertical lines are parallel, what do we know about their slopes? If two lines are perpendicular and neither is para
yanalaym [24]

Answer:

Two straight lines with slopes m and m' are parallel when m = m'

Two straight lines with slopes m and m' are perpendicular when m × m' = - 1.

Step-by-step explanation:

Let us assume that the two non-vertical lines in the slope-intercept form are

y = mx + c ........... (1) and  

y = m'x + c' ............ (2)

If those two lines are parallel then we can say the slope of them will be the same i.e. m = m'

Now, if given two straight lines (1) and (2) are perpendicular to each other and neither of them is parallel to the axes, then we can write m × m' = - 1. (Answer)

6 0
3 years ago
Which formula should be used to calculate the amount of paper needed?
bogdanovich [222]

Answer:

Step-by-step explanation:

I=PRT where I =interest P=principal, R=rate, and T =time is

3 0
3 years ago
How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
Read 2 more answers
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