Draw a cartesian plane, create a graph with the equation x = y^2 - 2
then substitute numbers into the equation so that it is true, to find points on the graph, e.g. substitute y with 1, you get
x = 1^2 - 2
x = 1 - 2 = -1, so when y = 1, x = -1, this point is (-1, 1)
for the next substitute y with 2,
x = 2^2 - 2
x = 4 - 2 = 2, the point is (2, 2)
you might want to try negative values of y
y = -1, x = (-1)^2 - 2
x = -1 the point is (-1,-1)
then plot the points on the graph
Answer:
what
Step-by-step explanation:
Answer:Exact Form:
4
√
5
Step-by-step explanation:
You want to undo the (-9 1/2), so you will add 9 1/2 to each side
Answer:

Step-by-step explanation:
The equation of a line in slope-intercept form is
y = mx + b
We need to find the slope, m, and the y-intercept, b.
The line we need is perpendicular to the line 2x + y = 8.
<em>The slopes of perpendicular lines are negative reciprocals.</em>
We solve the given equation for y to find the slope of the given line.
2x + y = 8
y = -2x + 8
The given line has slope -2.
The negative reciprocal of -2 is 1/2.
Our line has slope, m = 1/2.
Now we have
y = 1/2 x + b
Now we use the given point, (-2, 3), for x and y, using x = -2, and y = 3, and we solve for b.
y = 1/2 x + b
3 = 1/2 * (-2) + b
3 = -1 + b
4 = b
b = 4
Now we have
y = 1/2 x + 4
Answer: 