Question

LM is the midsegment of trapezoid ABCD. AB= x + 8, LM = 4x + 3, and DC = 187. What is the value of x?

Answer 1

$\frac{|DC|+|AB|}{2}=|LM|\\\\|AB|=x+8;\ |LM|=4x+3;\ |DC|=187\\\\substitute:\\\\\frac{187+x+8}{2}=4x+3\ \ \ \ /\cdot2\\\\195+x=8x+6\ \ \ /-195;\ /-8x\\\\-7x=-189\ \ \ /:7\\\\\underline{\underline{x=27}}$