So u get a codon chart it'll look like a circle with a bunch of letters. Then you use the letters u are given for every dash such as UCU and you go biggest to smallest letter until you hit an amino acid or stop then what you write down is that amino acid you hit. For an example, we'll use UCU. You go to the big letter U inside that big U will be a smaller C and inside that C will be a smaller U which leads to an amino acid or a stop codon. And you do this with every group of 3 letters. If one is missing it stops prematurely and if there is an extra when it may have a mutation. I hope that helped! If not there are YouTube videos out there that can help.
glucose is stored in carbon bonds
The answer is... Before entering meiosis I, a cell must first go through interphase. This is the same interphase that occurs before mitosis. The cell grows, copies its chromosomes and prepares for division. And to make it more simple the answer is meiosis. Hope this helps!
Answer:
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0
Explanation:
According to Levin's model (1969):
<em>dP/dt = c - e</em>
where P represents the proportion of occupied patches.
<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.
Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:
- if dP/dt >0, then P is increasing with time
- if dP/dt <0, then P is decreasing with time
- if dP/dt = 0, then P is remaining the same with time.
The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).
c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0 and 1.
As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.
