Answer:
Mass = 3.84 g
Explanation:
Given data:
Mass of hydrogen sulfide = 2.7 g
Mass of oxygen required = ?
Solution:
Chemical equation:
2H₂S + 3O₂ → 2H₂O + 2SO₂
Number of moles of hydrogen sulfide:
Number of moles = mass/ molar mass
Number of moles = 2.7 g / 34 g/mol
Number of moles = 0.08 mol
Now we will compare the moles of hydrogen sulfide with oxygen.
H₂S : O₂
2 : 3
0.08 : 3/2 ×0.08 = 0.12 mol
Mass of oxygen;
Mass = number of moles × molar mass
Mass = 0.12 mol × 32 g/mol
Mass = 3.84 g
They will not have to pay any cost because the accident was not Dave’s fault, Eli will be covered by Dave’s family car insurance policy, they will be protected by the other driver’s insurance. (B,C,D)
Explanation: just answered it and it was correct.
Answer:
Explanation:
First thing is we have assume all the percents are grams so we have
68.279g C, 6.2760g H, 3.7898g N, and 21.656g O
Now convert each gram to moles by dividing the the molar mass of each element
68.279g/12.01g= 5.685 moles of C
6.2760g/1.01g= 6.214 moles of H
3.7898g N/14.01g= 0.271 moles of N
21.656g O/ 16.00g= 1.354 moles of O
Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....
5.685 moles/0.271 moles ------> ~21 C
6.214 moles/0.271 moles --------> ~23 H
0.271 moles / 0.271 moles ---------> 1 N
1.354 moles/ 0.271 moles ----------> ~5 O
So the empirical formula is C21H23NO5
POH = -log [OH-]
pOH = - log (1 x 10^-11)
pOH = -(-11) = 11
pH + pOH = 14
pH + 11 = 14
pH = 14 - 11 = 3
ZnS(s) + 2O₂(g) ⇒ZnSO₄(s)
<h3>Further explanation</h3>
The oxidation-reduction reaction or abbreviated as Redox is a chemical reaction in which there is a change in oxidation number
Oxidation is an increase in oxidation number, while reduction is a decrease in oxidation number.
Reaction
ZnS(s) + 2O₂(g) ⇒ZnSO₄(s)
S²⁻ (-2 in ZnS) to S⁺⁶(+6 in ZnSO₄) ⇒ oxidation
O₂(0 in O₂) to O⁻²(-2 in ZnSO₄)⇒ reduction
