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antiseptic1488 [7]

3 years ago

9

There are 5 swimmers in a race. There will be a first-place, a second-place, and a third-place prize awarded. In how many differ

ent ways can the 3 prizes be awarded?

1 answer:

IrinaK [193]3 years ago

5 0

3 prizes for the first three people/ winners

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What is the solution of the inequality shown below

Eduardwww [97]

Answer:

there is no inequality..

Step-by-step explanation:

5 0

3 years ago

I was absent the day they taught this and my teacher refuses to teach me

julsineya [31]

Step-by-step explanation:

it's something in algebra i don't remember but basically the top number (12) has the x on the bottom which is multiplication and the bottom number (8) has addition so those tell u how ur supposed to get those numbers

so basically u need to find two numbers that add up to 8 and multiply to 12 so the factors are 6 and 2 because 6 • 2 is 12 and 6 + 2 = 8. hope this helps

7 0

3 years ago

Read 2 more answers

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

2 years ago

1.9/10 times 3/6 then simplified

givi [52]

1) 0.095
2)0.1875
3)0.3
4)0.21875
5)0.133
6)0.66
7) 0.6
8)0.375

8 0

4 years ago

Given: Triangles ABC and DBC are isosceles, m∠BDC = 30°, and m∠ABD = 155°. Find m∠ABC, m∠BAC, and m∠DBC.

just olya [345]

∠BDC=30, so ∠CBD + ∠BCD=180-30=150
ΔDBC is isosceles, so ∠CBD=∠BCD=half of 150=75
∠ABC=∠ABD-∠CBD=155-75=80
ΔABC is isosceles, so ∠ABC=∠ACB=80
∠BAC=180-80-80=20

7 0

4 years ago