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Vanyuwa [196]
3 years ago
5

The sum S of the first n integers is given by the formula S=1/2n(n+1). How many integers must be taken to have a sum of

Mathematics
1 answer:
statuscvo [17]3 years ago
5 0

Answer:

25

Step-by-step explanation:

We require to solve for n, hence

\frac{1}{2} n(n + 1) = 325

multiply both sides by 2 to eliminate the fraction

n(n + 1) = 650

n² + n = 650

subtract 650 from both sides to have equation in standard form

n² + n - 650 = 0 ← in standard form

(n + 26)(n - 25) = 0 ← in factored form

equate each factor to zero and solve for n

n + 26 = 0 ⇒ n = - 26

n - 25 = 0 ⇒ n = 25

however, n > 0 ⇒ n = 25


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Mrs smith invests £30,000 (some in a 5% account, some in an 8% account). After the year shes earned £2100. How much did she put
mixer [17]

Answer:

She deposited £10,000 in the 5% yield account and deposited £20,000 in the 8% yield account

Step-by-step explanation:

Let the amount she put in each account be £x and £y respectively

Total amount deposited is ;

x + y = 30,000 ••••••(i)

Now, let’s look at the earnings:

in the £x , amount earned would be;

5/100 * x = 5x/100

For the £y, amount earned would be;

8/100 * y = 8y/100

Adding both gives the total which is £2,1000

5x/100 + 8y/100 = 2,100

Multiply through by 100

5x + 8y = 210,000 ••••••••(ii)

From the first equation, we know that

x = 30,000 -y

Let’s put this into the second

5(30,000-y) + 8y = 210,000

150,000-5y + 8y = 210,000

3y = 210,000 -150,0000

3y = 60,000

y = 60,000/3

y = £20,000

So mathematically;

x = 30,000-y

x = 30,000 -20,000

x = £10,000

7 0
3 years ago
8. Find the common factors of 75,100 and 60​
yaroslaw [1]

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6 0
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7 0
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