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2 years ago

PLEASE HELP THE ONES I CIRCLE ARE THE ONES YOU DO

Mathematics

1 answer:

alexandr402 [8]2 years ago

4 0

Answer:

1 is a competition, 2 is protection, 5 is division, and 8 is solution.

Step-by-step explanation:

hope these are all correct and you ace this!

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2а + 20 = -3а - 5 pls help

sammy [17]

Answer: A= -5

Step-by-step explanation:

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2 years ago

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Calculate the value of angle A and C of ∆ ABC. Where b=1435cm, a= 782cm and B= 115.6°.

Monica [59]

The Law of Sines says

$\dfrac{\sin A}{a} = \dfrac{\sin B}{b} = \dfrac{\sin C}{c}$

$\sin A = \dfrac a b \sin B$

$A = \arcsin( \dfrac{782}{1435} \sin 115.6 ) = 29.44^\circ$

We don't have to worry about the obtuse supplement because a triangle can only have one obtuse angle, and that's B.

$C = 180 - 115.6 - 29.44 = 34.96^\circ$

Answer: A=29.44°, C=34.96°

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2 years ago

A farmer bought 16 sheep, with 100 dollar insurance on each of them. He then bought a $25 heater. If he paid $925, how much did

lubasha [3.4K]

$46
heater and insurance for each sheep subtracted from the total amount leaves $740. Then divided by the amount of sheep equals $46!
Hope I helped!

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2 years ago

15. An irregular pentagon has side lengths of (x + 3), (2x - 4), (4x + 5),

Tcecarenko [31]

I’m my opinion I thick it could be A

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3 years ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

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3 years ago