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ale4655 [162]
3 years ago
12

Help me with this pleaae

Mathematics
1 answer:
marissa [1.9K]3 years ago
6 0

Answer:

(D) 30pi inches

Step-by-step explanation:

First, we use the given volume, the given height, and the formula of the volume of a cylinder to find the radius of the base. Then we use the radius of the base to find the circumference of the base.

volume = \pi r^2 h

volume = 6750 \pi~in.^3

We set the formula equal to the volume and replace h with 30 in.

\pi r^2 h = 6750 \pi~in.^3

\pi r^2 \times 30 ~in. = 6750 \pi~in.^3

Divide both sides by 30pi in.

r^2 = 225 ~in.^2

Take the square root of each side.

\sqrt{r^2} = \sqrt{225 ~in.^2}

r = 15~in.

The radius of the base is 15 in.

Now we use the radius of the base and the formula of the circumference of a circle to find the answer.

circumference = 2 \pi r

circumference = 2 \pi \times 15~in.

circumference = 30 \pi ~in.

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The cost of a taxi ride includes an initial charge of $2.00. If a 5km ride cost $6.00 and 10km ride cost $10.Oo, determine the c
romanna [79]

Answer:

5km costs $4

if you take the intial charge of $2, you're paying $4 per 5km

hence 10km= 2 *5km= 2*$4=$8+initial charge $2= $10

15Km= 3*5km= 3*$4= $12 + intial charge $2 = $14

Step-by-step explanation:


4 0
3 years ago
Which is a y-intercept of the graphed function
dybincka [34]

Answer:

\displaystyle (0, -9) \\ (0, -3)

Step-by-step explanation:

There is no graph posted, but y-intercepts are <em>x</em>'s are set equal to zero.

I am joyous to assist you anytime.

4 0
3 years ago
A Packaging Company produces boxes out of cardboard and has a specified weight of 16 oz. A random sample of 36 boxes yielded a s
user100 [1]

Answer:

The margin of error is of 0.73 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{1.7}{\sqrt{36}} = 0.73

The margin of error is of 0.73 oz.

The lower end of the interval is the sample mean subtracted by M. So it is 15.3 - 0.73 = 14.57 oz.

The upper end of the interval is the sample mean added to M. So it is 15.3 + 0.73 = 16.03 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

4 0
3 years ago
MARK AS BRAINLEST
WARRIOR [948]

Answer:

{- 2, - 4, - 6, - 8, - 10 }

Step-by-step explanation:

Given

f(x) = 2x - 6 with domain { - 2, - 1, 0, 1, 2 }

To obtain the range substitute the values of x from the domain into f(x)

f(- 2) = 2(- 2) - 6 = - 4 - 6 = - 10

f(- 1) = 2(- 1) - 6 = - 2 - 6 = - 8

f(0) = 2(0) - 6 = 0 - 6 = - 6

f(1) = 2(1) - 6 = 2 - 6 = - 4

f(2) = 2(2) - 6 = 4 - 6 = - 2

Range is { - 2, - 4, - 6, - 8, - 10 }

6 0
3 years ago
The diagram shows rays of light from a point source, P, that reach a detector, D, along two paths. One path is a straight line,
tatiyna
This can solved using the cosine law which is:
c² = a² + b² - 2ab cos θ
Using the values given from the problem
6² = b² + b² - 2bb cos 112.62
And solving for b
36 = 2b² - 2b² cos 112.62
b = 3.6

The answer is the 3rd option.
8 0
3 years ago
Read 2 more answers
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