Answer:
The area of the regular hexagon is 
Step-by-step explanation:
we know that
The area of a regular hexagon can be divided into 6 equilateral triangles
so
step 1
Find the area of one equilateral triangle
we have
----> is the apothem
substitute
step 2
Find the area of 6 equilateral triangles
The answer is:
y = 3x - 8
Find b by plugging in the point (x,y) which is (3,1).
1= 3(3)+b
1= 9 + b
-8 = b
I’m pretty sure it’s x=10 because
8x + 50 = 130
So we would subtract 50 from both sides so it would be 8x = 130 - 50 then it would give us 80 so now we have 8x =80, now we will need to divide the 8 on both sides to get x, so 80/8 equals 10
I know of two ways to solve quadratic equations. The first is through factoring. Let us take the example (x^2)+2x+1=0. We can factor this equation out and the factors would be (x+1)(x+1)=0. To solve for the roots, we equate each factor to 0, that is
x+1=0; x+1=0
In this case, the factors are the same so the root of the equation is
x=1.
The other way is to use the quadratic formula. The quadratic formula is given as [-b(+-)sqrt(b^2-4ac)]/2a where, using our sample equation above, a=1, b=2 and c=1. Substitute these to the formula, and you will get the same answer as the method above.
