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tia_tia [17]
3 years ago
11

Can anyone add me on ig or discord and send me some exam papers or lesson about 8th grade? (math)

Mathematics
1 answer:
Artemon [7]3 years ago
6 0

Answer:

i can send you questions of class 8

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What is the answer to number 7b?
Semmy [17]
Increasing it by 10% will be 11.55. To find teen percent all you do is make it a decimal then multiplying it by 10.50
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3 years ago
Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have one digit followed
Alekssandra [29.7K]

Answer:  The required number of passwords that can be created is 175760.

Step-by-step explanation:  Given that a company needs temporary passwords for the trial of a new payroll software.

Each password will have one digit followed by three letters and the letters can be repeated.

We are to find the number of passwords that can be created using this format.

For the one digit in the password, we have 10 options, 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Since there are 26 letters in English alphabet and letters can be repeated, so the number of options for 3 letters is

26 × 26 × 26 = 17576.

Therefore, the total number of ways in which passwords can be created using the given format is

n=9\times17576=175760.

Thus, the required number of passwords that can be created is 175760.

3 0
3 years ago
find the slope of the line that has the following intercepts: y-intercept: -15; x-intercept: 3. round your answer to 1 decimal p
Readme [11.4K]
Y intercept : (0,-15)
X intercept : (3,0)

Slope : (0 - (-15)) / (3-0) = 15 / 3 = 5
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3 years ago
I don’t understand how to do 8. , 9. , and 10.
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2 years ago
18. Determine the common difference, the fifth term, and the sum of the first 100 terms of the following sequence:
Ksenya-84 [330]

a_1=1,\ a_2=2.5,\ a_3=4,\ a_4=5.5,\ ...\\\\a_2-a_1=2.5-1=1.5\\a_3-a_2=4-2.5=1.5\\a_4-a_3=5.5-4=1.5\\a_{n+1}-a_n=1.5=constans\\\\\text{It's an arithmetic sequence with}\\a_1=1,\ \boxed{d=1.5}\\\\a_n=a_1+(n-1)d\to a_n=1+(n-1)(1.5)=1+1.5n-1.5\\\\a_n=1.5n-0.5\\\\a_5=1.5(5)-0.5=7.5-0.5=7\\\boxed{a_5=7}\\\\\text{The formula of a Sum of the First n Terms of an Arithmetric Sequence:}\\\\S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n\\\\\text{We have:}\\a_1=1,\ d=1.5,\ n=100\\\\\text{Substitute}

S_{100}=\dfrac{(2)(1)+(100-1)(1.5)}{2}\cdot100=\dfrac{2+(99)(1.5)}{1}\cdot50\\\\=(2+148.5)\cdot50=150.5\cdot50=7,525\\\\\boxed{S_{100}=7,525}\\\\Answer:\\the\ common\ difference:\ d=1.5\\the\ fifth\ term:\ a_5=7\\the\ sum\ of\ first\ 100\ terms:\ S_{100}=7,525

8 0
3 years ago
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