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3 years ago

Consider (2x – 1) + 2 > x + 1. Use the addition or subtraction

Mathematics

1 answer:

AfilCa [17]3 years ago

7 0

Answer:

x>0

Step-by-step explanation:

subtract 1 from both sides
subtract x from both sides
x>0

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PLEASE HELP ME AS SOON AS POSSIBLE!!!!!! FIVE AND SIX PLEASE

Murljashka [212]

Answer:

5 infinitely

6 i think its 2

Step-by-step explanation:

6 0

3 years ago

What is the solution of the system of equations? 3x + 6y = –2 15x + 30y = –10

cestrela7 [59]

3x + 6y = -2......multiply by -5
15x + 30y = -10
--------------------
-15x - 30y = 10 (result of multiplying by -5)
15x + 30y = -10
--------------------add
0 = 0

there are infinitely many solutions

7 0

4 years ago

Read 2 more answers

50 children had a choice of beans,plantain and rice.21 of them took beans,24 took plantain and 18 took rice.3 took beans only an

faltersainse [42]

The Venn diagram to illustrate this information is given in the image attached.

<h3>What is the Venn diagram about?</h3>

The number of children who took plantain and beans only are:

Let beans = a

Rice = b

Plantain = P

So: a + b = 24 - 9 - 5 = 10

Note that 24 children took plantain.

9 children took only Plantain.

5 took the 3 food items.

So:

b + c = 18 -2 - 5 = 11

a + c = 21 - 3 - 5 = 13

P∩B = a + 5

= 6 + 5 = 11

R ∩ B = C + 5

=7 + 5 = 12

None of the three items of food =

50 - (3 + 2 + 9 + 6 + 4 + 7 + 5)

= 50 - 36

=14

Learn more about Venn diagram from

brainly.com/question/2099071

#SPJ1

4 0

2 years ago

Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago

How would yo expand ln (1/49k)?

dedylja [7]

Answer:

Step-by-step explanation:

It depends on whether you mean ln(1/49k) or ln(1/(49k)).

3 0

3 years ago