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ivanzaharov [21]
3 years ago
13

X+3=4x-6 What is the value of x?

Mathematics
2 answers:
UNO [17]3 years ago
5 0

Answer:

3

Step-by-step explanation:

kakasveta [241]3 years ago
3 0

Answer:

Step-by-step explanation:

subtract x from both sides

you get 3x-6=3

add 6 to 3

3x=9

x=3

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6. 150 is 75% of what number?
lora16 [44]

Answer: 8.2

Step-by-step explanation: So the way i do it is first i see that 6.15 is 75% of a number, and i know that 75% is 3/4. so i start by divided 6.15 by 3, and getting 2.05. i then times it by 4, making it 4/4. Therefore, getting 8.2

4 0
3 years ago
Read 2 more answers
-4r-11=4r+21 pls help <br>​
Masja [62]

-4r-11=4r+21

Move 4r to the other side

Sign changes from +4r to -4r

-4r-4r-11=4r-4r+21

-4r-4r-11=21

-8r-11=21

Move -11 to the other side

Sign changes from -11 to +11

-8r-11+11=21+11

-8r=21+11

-8r=32

Divide both sides by -8

-8r/-8=32/-8

Answer: r=-4

8 0
3 years ago
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Find each value if f(x) = 2x - 1 and g(x) = 2 - x2.
bixtya [17]
Well i don’t know i just need me pints but sorry i’m so sorry
3 0
3 years ago
What is the solution set of the following equation? -8x + x + 15 = -7 x + 12 ​
UNO [17]

Answer:

I dont k ow what the following set for your equation is...

3 0
2 years ago
Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

8 0
3 years ago
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