Answer:
10x²+11-2x
Step-by-step explanation:
I hope you mean 7x²+8+5, not 7x²+8x+5.
We need to combine like terms. Anything with squared should be added together, et cetera.
(7x²+8+5)+(3x²-2x-2)
You can take out the parenthesis, because they don't matter in addition.
7x²+8+5+3x²-2x-2
Add the terms, step by step. Each bold pair needs to be added together.
7x²+8+5+3x²-2x-2
10x²+8+5-2x-2
10x²+11-2x
Now there's no more we can add together.
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
24%
Step-by-step explanation:
Given: Regular price of two item is $30 and $20.
60% discount provided on second item.
Now, lets find out discount provided on second item.
∴Discount provided = 
Amount paid for second item = Regular price - discount provided
∴Amount paid on second item= 
Total amount paid for two item= Regular price of first item + discounted price of second item.
∴Total amount paid for two item= 
Next, lets find out the percent of reduced total cost of two item.


∴ By
the total cost of two item reduce during sale.
The answer is the first one. p>-2 and p<5. you must choose the first one because the circle is uncoloured
Yes, 13 is the remainder.
See dat pic for full solution.