The sequence diverges because the value of the absolute common ratio r is greater than the 1.
<h3>What is convergent of a series?</h3>
A series is convergent if the series of its partial sums approaches a limit; that really is, when the values are added one after the other in the order defined by the numbers, the partial sums getting closer and closer to a certain number.
We have series:
9, 27, 81, 243....
The above series is a geometric progression with common ratio r is 3
r = 3
We know the formula for a geometric sequence:
A geometric series converges only if the absolute value of the common ratio:
r < 1 and
It diverges if the ratio ≥ 1
Here the value of r = 3 which is greater than the 1 so the sequence diverges.
Thus, the sequence diverges because the value of the absolute common ratio r is greater than the 1.
Learn more about the convergent of a series here:
brainly.com/question/15415793
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The answer is:
y = x - 4
m is the gradient.
c is the y-intercept
Hope this helps!
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Answer:
1/3
Step-by-step explanation:
Let A be the event that you grab the fair coin and B be the event that you toss a tail.
P(A) is the probability that you grab the fair coin, which is 1/3
P(B) is the probability that you toss a tail, which is 1/2
P(B|A) is the probability that you toss a tail, given that you grab a fair coin, which is 1/2
P(A|B) is the probability that you grab the fair coin, given that you toss a tail, which we are looking for.
Using Bayes probability theorem we have:
This question is incomplete because it was not written properly
Complete Question
A teacher gave his class two quizzes. 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first one passed the second quiz? (2 points)
a) 20%
b) 40%
c) 60%
d) 75%
Answer:
d) 75%
Step-by-step explanation:
We would be solving this question using conditional probability.
Let us represent the percentage of those who passed the first quiz as A = 80%
and
Those who passed the first quiz as B = unknown
Those who passed the first and second quiz as A and B = 60%
The formula for conditional probability is given as
P(B|A) = P(A and B) / P(A)
Where,
P(B|A) = the percent of those who passed the first one passed the second
Hence,
P(B|A) = 60/80
= 0.75
In percent form, 0.75 × 100 = 75%
Therefore, from the calculations above, 75% of those who passed the first quiz to also passed the second quiz.
