What is the flaw in Gina’s proof?
A) Points D and E must be constructed, not simply labeled, as midpoints.
B) Segments DE and AC are parallel by construction. THIS IS THE FLAW. THE SEGMENTS WERE NOT DRAWN NOR PROPERLY IDENTIFIED.
C) The slope of segments DE and AC is not 0.
D) The coordinates of D and E were found using the Distance between Two Points Postulate
Angle KMQ and angle RNL are on apposite sides of the transversal and between above and below (exterior to) the parallel lines, so they are alternate exterior angles. Theorem - Alternate exterior angles formed by parallel lines and a transversal have the same measure.
Answer:
Therefore,
Step-by-step explanation:
Simplify
-2^3
It is read as negative 2 raised to the power three,
also it is the cube of negative 2
we know that 
given as
so for negative a i.e -a
substituting a = 2 we get
negative sign multiplied by odd number of times then the sign remains negative.
Therefore,
I can’t seen the question so it is hard to answer
Hello from MrBillDoesMath!
Answer:
See Discussion below
Discussion:
A function f is even if f(-x) = f(x)
f(x) f(-x) Are they equal?
----------------------------------------------------------------------------------------
-x^8 + 2x^6-5x -(-x)^8 + 2(-x)^6 + 5x No
3 abs(x) - 4 3 abs(-x) -4 Yes
log5 x^2 log5 (-x)^2 Yes
(6x)^ (1/7) (-6x)^(1/7) No
e^(x^2-x) e^( (-x)^2+x) No
(x^8 +5x^2)^(-1) ( (-x)^8 + 5 (-x)^2) ^(-1) Yes
Answers with Yes, above are even functions.
Regards,
MrB
P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!
