Solution:
<u>We know that:</u>



<u>Simplify the equation to find the percent off:</u>

![84\% + \bold{16\%} = 100\% \space\ \space\ \space\ \ \ \ \ [Rounded]](https://tex.z-dn.net/?f=84%5C%25%20%2B%20%5Cbold%7B16%5C%25%7D%20%3D%20100%5C%25%20%5Cspace%5C%20%5Cspace%5C%20%5Cspace%5C%20%5C%20%5C%20%5C%20%5C%20%5BRounded%5D)
This means that the <u>original price</u> has decreased about 16%.
Answer:
1. 11t
2.7w+28
3. 2c+11
4. 8n
5. 10r+15
6. 24−8g
7. 17d−9
8. 8g+7z
9. 23b
10. 2rs+1
11. 9f+9g
12. 4x+y
13. 21a+14
14. 21a+14
15. 6−3k
16. 18n+36
17. 9s+3t
18. 8a−12b
19. 11m+n
20. 2+6z
21. 8x+6y
22. 7hg−7
23. 4st+5
24. 2r+17
25. 7w+6
26. 3(c+2)
27. 8f−4g
28. 2+8q+3r
Step-by-step explanation:
there you go, sorry it took so long
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)
moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g
Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05
N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
I’m not really for sure...but
I’d say it’s
x is negative and y is negative
Hope I’m Correct Sorry If I’m Not :)
Answer:
8:3
16:6
Step-by-step explanation:
First, let's check if 9 and 24 have any common factor. If they do have any common ones, we must find the GCF (greatest common factor).
Factors of 9: 1, 3, 9
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
The common factors both of the numbers share and 1 and 3. To find the GCF, simply compare one of the factors to the other.
1 < 3
Now that we know the GCF, we can divide the two numbers in the ratio 24 : 9 by it (3).
24:9
24/3:9/3
<u>8:3</u>
Now that our ratio is simplified, it's going to be much easier to find more ratios that are equivalent. <u>8:3</u> is already one equivalent ratio, but if we multiply each number in the ratio by any other number, we can get a new equivalent ratio. Let's multiply each number in the ratio by 2:
<u>8:3</u>
8 ⋅ 2:3 ⋅ 2
<u>16:6</u>
<u></u>
So, another equivalent ratio to 24:9 (and <u>8:3</u>) is <u>16:6</u>.