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NemiM [27]
4 years ago
9

The mean score of 8 players is 14.5. If the highest individual score is removed the mean of the score of the remaining 7 players

is 12. What is the highest score.
Mathematics
1 answer:
AfilCa [17]4 years ago
4 0

Answer:

The highest score is 32.

Step-by-step explanation:

We are given the following in the question:

The mean score of 8 players is 14.5.

Let x denote the highest score.

If x is removed, the mean of the score of the remaining 7 players is 12.

Formula for mean:

\bar{x} = \dfrac{\displaystyle\sum x_i}{n}

Putting values, we get:

14.5 = \dfrac{\displaystyle\sum x_i}{8}\\\\\Rightarrow \displaystyle\sum x_i = 116\\\\12 = \dfrac{\displaystyle\sum y_i}{7}\\\\\Rightarrow \displaystyle\sum y_i  = 84\\\\\displaystyle\sum y_i = \displaystyle\sum x_i -x \\\\84 = 116 - x\\\Rightarrow x = 32

Thus, the highest score is 32.

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Because the tell if he number is big or small
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How do I factor 8+16
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8+16 the gcf is 8

Step-by-step explanation:

You look for the GCF

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Suppose an airport metal detector catches a person with metal 99% of the time. That is, it misses detecting a person with metal
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Step-by-step explanation:

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8 0
3 years ago
Find the LCM of 132 and 60 using Prime Factorization ?
Sav [38]

Answer:

660

Step-by-step explanation:

First, let's find the prime factorization for both numbers.

132 = 11 x 12

12 = 3 x 4

4 = 2 x 2

<u>132 = 2 x 2 x 3 x 11</u>

60 = 5 x 12

12 = 3 x 4

4 = 2 x 2

<u>60 = 2 x 2 x 3 x 5</u>

Now, to find the lowest common multiple, we just need to multiply each number the most times it is seen in either number.

<u>132 = 2 x 2 x 3 x 11</u>

<u>60 = 2 x 2 x 3 x 5</u>

The first number is both is 2, which appears at most twice in either list so we will multiply two 2s to find the LCM.

Both numbers also have at most one 3, one 5, and one 11, so to find our LCM, we just need to multiply all these numbers together:

2 x 2 x 3 x 5 x 11 = 660

The LCM of 132 and 60 is 660.

Hope this helped!

4 0
3 years ago
Find the absolute minimum and absolute maximum of f(x,y)=14−7x+10y f(x,y)=14−7x+10y on the closed triangular region with vertice
Black_prince [1.1K]

Answer:

Maximum value of f(x,y) at (10,13)=74

Minimum value of f(x,y) at (10,0)=-56

Step-by-step explanation:

We are given that

f(x,y)=14-7x+10y

Vertices are (0,0),(10,0) and (10,13)

Substitute x=0 and y=0

f(0,0)=14-0+0=14

Substitute x=10 and y=0

f(10,0)=14-7(10)+10(0)=14-70=-56

Substitute x=10 and y=13

f(10,13)=14-7(10)+10(13)=14-70+130=74

Maximum value of f(x,y) at (10,13)=74

Minimum value of f(x,y) at (10,0)=-56

7 0
3 years ago
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