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Nuetrik [128]
3 years ago
14

Estimate 7.411*47hhhhhhhhhhhhh

Mathematics
1 answer:
jenyasd209 [6]3 years ago
6 0

7*50=350

350 is da answer so yeah

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How do you solve (7^-1)^-1 and 5^2 * 5^4 * 5^-3
Katyanochek1 [597]

Answer:

Step-by-step explanation:

exponents raised to a - power  is an inverse function probably not the right word

       a^-b    =  1/(a^b)     example       4^-2   = 1/(4^2)     =  1/16

so   (7^-1)^-1  is a double inverse which is back to the original number  7

      inverted 7 twice

      (7^-1)^-1     = (1/7)^-1     =  1/(1/7)     =   7     trust me or use your calculator

since the coeffients are the same  just add the powers...  some exponent rule

     5^2 * 5^4 * 5^-3   = 5^(2+4-3)   = 5³

here is it written out

5^2 * 5^4 * 5^-3    = 5²  ×   5^4   ×  5^-3    =   (5×5) × (5×5×5×5)  × (1/5×1/5×1/5)

    5×5 × 5× (5×5×5  × 1/5×1/5×1/5)           (5×5×5  × 1/5×1/5×1/5)  = 1

    5×5×5    = 5³

   so

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3 years ago
Terri wrote the system of linear inequalities.
tiny-mole [99]

Answer:

Step-by-step explanation:

A,b,d

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3 years ago
Rashad wants to buy a TV which is $235. He already has $35. If he saves $25 a week. For at least how many weeks he has to save m
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3 years ago
What is the range of the function defined as y=5
seraphim [82]
\bf \begin{array}{cllll}
x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
-7&5^{-7}\to \frac{1}{5^7}\to \frac{1}{78125}\\\\
-3&5^{-3}\to \frac{1}{5^3}\to \frac{1}{125}\\\\
0&5^0\to 1\\\\
3&5^3\to 125\\\\
7&5^7\to 78125
\end{array}

so... you can keep on going towards the negatives with "x", or towards the positives with "x", notice, if the "x" is negative, "y" is just a fraction, positive, but a fraction

and if "x" is positive, "y" is a positive integer
even when x =0, "y" never became 0, and is never negative either

so, the range is, "y" is always positive, but not 0, or  y>0
6 0
4 years ago
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