All categories

3 years ago

Please answer correctly, thanks!

Mathematics

1 answer:

OlgaM077 [116]3 years ago

4 0

Answer:

940

Step-by-step explanation:

Put it in a problem

230 · 0.15x = 371

Then, subtract 230 from both sides

0.15x = 141

Divide both sides by 0.15

x = 940

You might be interested in

Let S be the solid beneath z = 12xy^2 and above z = 0, over the rectangle [0, 1] × [0, 1]. Find the value of m > 1 so that th

jonny [76]

Answer:

The answer is $\sqrt{\frac{6}{5}}$

Step-by-step explanation:

To calculate the volumen of the solid we solve the next double integral:

$\int\limits^1_0\int\limits^1_0 {12xy^{2} } \, dxdy$

Solving:

$\int\limits^1_0 {12x} \, dx \int\limits^1_0 {y^{2} } \, dy$

$[6x^{2} ]{{1} \atop {0}} \right. * [\frac{y^{3}}{3}]{{1} \atop {0}} \right.$

Replacing the limits:

$6*\frac{1}{3} =2$

The plane y=mx divides this volume in two equal parts. So volume of one part is 1.

Since m > 1, hence mx ≤ y ≤ 1, 0 ≤ x ≤ $\frac{1}{m}$

Solving the double integral with these new limits we have:

$\int\limits^\frac{1}{m} _0\int\limits^{1}_{mx} {12xy^{2} } \, dxdy$

This part is a little bit tricky so let's solve the integral first for dy:

$\int\limits^\frac{1}{m}_0 [{12x \frac{y^{3}}{3}}]{{1} \atop {mx}} \right.\, dx =\int\limits^\frac{1}{m}_0 [{4x y^{3 }]{{1} \atop {mx}} \right.\, dx$

Replacing the limits:

$\int\limits^\frac{1}{m}_0 {4x(1-(mx)^{3} )\, dx =\int\limits^\frac{1}{m}_0 {4x-4x(m^{3} x^{3} )\, dx =\int\limits^\frac{1}{m}_0 ({4x-4m^{3} x^{4}) \, dx$

Solving now for dx:

$[{\frac{4x^{2}}{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right. = [{2x^{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right.$

Replacing the limits:

$\frac{2}{m^{2} }-\frac{4m^{3}\frac{1}{m^{5}}}{5} =\frac{2}{m^{2} }-\frac{4\frac{1}{m^{2}}}{5} \\ \frac{2}{m^{2} }-\frac{4}{5m^{2} }=\frac{10m^{2}-4m^{2} }{5m^{4}} \\ \frac{6m^{2} }{5m^{4}} =\frac{6}{5m^{2}}$

As I mentioned before, this volume is equal to 1, hence:

$\frac{6}{5m^{2}}=1\\m^{2} =\frac{6}{5} \\m=\sqrt{\frac{6}{5} }$

3 0

3 years ago

I need to know the answer

MissTica

If Sachiko lets x represent the length of the side of the square and she wants to find the length of the perimeter of the square, it is appropriate for her to ...

... B. Set the area equal to x², solve for x, and then multiply the value of x by 4.

_____

The area of a square of side length x is x·x = x². The perimeter of a square of side length x is x+x+x+x = 4·x.

3 0

3 years ago

Please solve this, x=1/(2-√3) y=1/(2+√3) x^4+y^4=?

Charra [1.4K]

Answer:4y

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

PLZZZZ HELPPPP!!!!!! 12 POINTS!!!

Paha777 [63]

Plug in each pair into each system of inequalities. And see which one fits

4 0

3 years ago

Mixed number as a percent I'm so dumb

Maurinko [17]

The mixed number as a percent is 0.34%

6 0

3 years ago