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levacccp [35]
2 years ago
7

A chef has 2 blocks of butter. Each block weighs 1 pound. She cuts each block into fifths

Mathematics
1 answer:
Zepler [3.9K]2 years ago
5 0
She would have 10 blocks of butter each weighing .20 pounds
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Please I need this question ASAP
makkiz [27]
In order to find all of these, you first must convert the percentage to a decimal. This would be 13% to 0.13.

Now, multiply 0.13 by all of these into a calculator.

1800 • 0.13 = 234
950 • 0.13 = 123.50
2200 • 0.13 = 286
3000 • 0.13 = 390
2600 • 0.13 = 338
7 0
3 years ago
Solve for 6y+12=3y-3
kherson [118]
6y + 12 = 3y - 3

Subtract 3y on both sides

3y + 12 = -3

Subtract 12 on both sides

3y = -15

Divide by 3 on both sides

y = -5
5 0
3 years ago
Read 2 more answers
What are the equations of the lines with the given slope and y-intercept
Stella [2.4K]

Answer:

1. y=2x-3

2. y=4x-2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the value of the shown expression? 33 x 3-2 A) -54 B) -243 C) 243 D) 3
alex41 [277]

We have the following general rule for exponents:

a^n\cdot a^m=a^{n+m}

then, in this case we have the following:

3^3\cdot3^{-2}=3^{3+(-2)}=3^{3-2}=3^1=3

therefore, the answer is 3

4 0
1 year ago
determine the base, b, of the exponential model. Is the base a growth or decay factor? a. b is 0.6394; It is a growth factor. b.
Kazeer [188]
An exponential model can be described by the function
f(x) = a(b)^x
where: a is the initial population or the starting number, b is the base and x is the number of periods elapsed.

When the base of an exponential model is greater than 1 it is called a growth factor, but when it is less than 1 it is called a decay factor.

Given the exponential model
n=20.5(0.6394)^t
n is the final output of the exponential model, 20.5 is the starting number, 0.6394 is the base and t is the number of periods/time elapsed.

Here, the base is 0.6394 which is less than 1, hence a decay factor.

Therefore, <span>the base, b, of the exponential model is 0.6394; It is a decay factor.</span>
8 0
3 years ago
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