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2 years ago

Which type of evidence uses information gained through research? A. empirical B. statistical C. anecdotal D. analogical

Mathematics

1 answer:

Effectus [21]2 years ago

6 0

The answer is A. empirical.

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If sin 0 = 7/25, find csc 0

kipiarov [429]

Answer:

$csc(\theta)=\frac{25}{7}$

Step-by-step explanation:

We know that:

$sin(\theta)=\frac{7}{25}$

And we want to find:

$csc(\theta)$

Remember that there is a trigonometric identity that relates the $sin(\theta)$ function with the $csc(\theta)$ function

$csc(\theta)=\frac{1}{sin(\theta)}$

Then if $sin(\theta)=\frac{7}{25}$ this means that:

$csc(\theta)=\frac{1}{\frac{7}{25}}$

Finally:

$csc(\theta)=\frac{25}{7}$

3 0

2 years ago

Read 2 more answers

Given that x = 3, y = -2 and z = 0, calculate the value of each of the following algebraic expressions: 2x + y. Answer quick ple

icang [17]

2 times 3+(-2)
6-2
4. Is the cord answer

4 0

2 years ago

Factor the following polynomial completely 6x^5-30x^4-84x^3

Andrei [34K]

Answer:

6x^3(x+2)(x-7)

Step-by-step explanation:

1st step: factor out common term, 6x^3(x^2 - 5x - 14)

2nd step: Factor x^2 - 5x - 14, (x + 2)(x - 7)

3rd step: simplify, 6x^3(x+2)(x-7)

I am joyus to assist :)

8 0

2 years ago

The graph shows the solution to which system of inequalities?

postnew [5]

Answer:

is A B and D

Step-by-step explanation:

5 0

2 years ago

Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr and then for another 2 hours and 5 minutes with a constant

NemiM [27]

The complete question is
<span>Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr and then for another 2 hours and 5 minutes with a constant speed of 12 km/hr what is her average speed for the total trip?</span>

we know that
speed=distance/time

1) Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr
time=2 1/6 hrs----> 13/6 hrs
speed=6 km/h
distance=speed*time----> 6*(13/6)---> 13 km

2)for another 2 hours and 5 minutes with a constant speed of 12 km/hr
time=2hrs+5 minutes----> 2+(5/60)--> 125/60 hrs
speed=12 km/hrs
distance=speed*time----> 12*(125/60)---> 25 km

3) find the average speed for the total trip
total distance=13 km+25 km----> 38 km
total time=(13/6)+(125/60)----> (10*13+125)/60----> 4.25 hours
speed=38/4.25----> 8.94 km/hrs

the answer is
8.94 km/hrs

7 0

3 years ago