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Aleks [24]
3 years ago
12

How has a rise on global temperature impacted the life of the polar bear? A rise in temperatures has disrupted the Arctic food c

hain common to polar bears. Key to maintaining a healthy weight and insulative fat layer is a diet of seals. The US Geological Survey suggest that if such trends continue, two-thirds of the world's Arctic ice could disappear by 2050. The accumulation of greenhouse gases in the Earth's atmosphere has been substantially increased by the combustion of fossil fuels. Scientists predict that malnourishment among the bears resulting in smaller litter sizes will result in their extinction in several decades. As a result of melting sea ice, there should be more vegetation on-shore for the polar bears to eat.
Biology
1 answer:
DIA [1.3K]3 years ago
4 0

Answer: A rise in temperatures has disrupted the Arctic food chain common to polar bears.

Explanation:

Global warming is the sustained increase in the average temperature of the earth, sufficient to cause climate change.

This rise in temperature has denied polar bear the presence of ice caps, that they usually get on in their hunts for seals. Consequently, the Arctic FOOD CHAIN has been disrupted, as polar bears are less likely to feed on seals

Note that other options DO NOT give the impact of global warming on polar bears

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3 years ago
Sean wants to know the effects of seawater on plant growth.<br> What is the dependent variable?
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2 years ago
What happens to a series circuit consisting of three light bulbs if a new light bulb is added to the circuit?
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8 0
2 years ago
A locus that affects susceptibility to a degenerative brain disease has two alleles, V and v. In a population, 16 people have ge
Pie

Answer:

Yes, the population is evolving

Explanation:

Hardy-Weinberg equilibrium states that a population is not evolving if it is in hardy weinberg equilibrium as the alleles frequency do not change over time in generations.

In mathematical equation, the genotype frequency will be -P²+2Pq+q²=1 and allele frequency will be p+q=1, where p = dominant allele and q will be recessive allele.

In the question, since the observed genotype are-

P² - VV= 16

2Pq- Vv- 92

q²- vv- 12

<u>1. Calculate allele frequency</u>

Now we will calculate if the expected value is same or close or not.

We will calculate allele frequency

Population has 120 individuals which means it has - 240 alleles.

In which V (p) will be- 32 +92= 124 allele

p- dominant allele/ total allele=  124/ 240 = 0.52

P= 0.52

q will be 1-0.52= 0.48

<u>2. Expected genotype frequency</u>

Now we will calculate expected genotypic frequency.

P²- 0.52 X 0.52= 0.27

2Pq = 2 x 0.52x 0.48 =  0.5

q²= 0.48 x 0.48 =  0.23

<u>3. Expected progeny </u>

P²= 0.27 x 120= 32 VV

2Pq= 0.5 X 120= 60 Vv

q²= 0.23 x 120= 28 vv

Since the observed value is not equal to the expected value therefore the population is not in Hardy- Weinberg equilibrium and the population is evolving.

Thus, Yes, the population is evolving is correct.

4 0
3 years ago
Read 2 more answers
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