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3 years ago

What is the value of x????

Mathematics

2 answers:

Serggg [28]3 years ago

6 0

Answer:

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 =c^2 where a and b are the legs and c is the hypotenuse

x^2 + 12^2 = 13^2

x^2 +144 =169

Subtract 144 from each side

x^2 +144-144 =169-144

x^2 = 25

Take the square root of each side

sqrt(x^2) = sqrt(25)

x=5

DaniilM [7]3 years ago

4 0

Answer:

the answer is 6

Step-by-step explanation:

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scZoUnD [109]

Answer:

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Step-by-step explanation:

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2 years ago

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Vikki [24]

Answer:

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Step-by-step explanation:

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3 years ago

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Use the law of cosines to find the value of 2*3*4 cos theta.

daser333 [38]

The law of cosines :

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3 years ago

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OOOO

lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

$x^4+95x^2 -500=0$

Substituting $x^2=a,$ given bi-quadratic equation reduces in the form of following quadratic equation:

$a^2 +95a -500=0\\$

Let us factorize the above quadratic equation:

$a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\$

Since square root of a negative number cannot be found, so:

$x \neq \pm \sqrt{-100}\\$

$CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\$

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Vlad [161]

Answer: C is the answer

Step-by-step explanation:

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