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3 years ago

Find the absolute value of 9.8 and of -10/3.

2 answers:

8 0

The absolute value of 9.8 is 9.8. The absolute value of -10/3 is found by using your order of operations like so:
-10÷3= -3.333...
l-3.333...l = 3.333...

xz_007 [3.2K]3 years ago

6 0

By definition, the absolute value of a number is given by:
$| a | = a
$
Where,
The number a is a real number. This means that the value of a is both negative and positive.
The result is always greater than zero.
Therefore, the absolute value of the given numbers is given by:
$|9.8| = 9.8$
$|-\frac{10}{3}| = \frac{10}{3}$
Answer:
the absolute value of 9.8 and of -10/3 is:
$|9.8| = 9.8$
$|-\frac{10}{3}| = \frac{10}{3}$

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An instructor gives her class the choice to do 7 questions out of the 10 on an exam.

Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

$10C7=\frac{10!}{7!(10-7)!}=120$

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

$(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50$

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

$(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50$

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

$(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10$

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0

3 years ago

What's the equation of the graph shown above?

nadezda [96]

Answer:

dfdff3ffdcdcdcd

Step-by-step explanation:

ccdcdcc

4 0

3 years ago

Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated

Dafna11 [192]

<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0

4 years ago

look at this equation and the steps used to solve it. Which answer is the best justification for step 1 of this solution

Julli [10]

Answer:

Step-by-step explanation:

4 0

3 years ago

Sorry, but I also need help on this

Fudgin [204]

Answer:

I think it's A

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers