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Nimfa-mama [501]
3 years ago
7

Find the absolute value of 9.8 and of -10/3.

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0
The absolute value of 9.8 is 9.8. The absolute value of -10/3 is found by using your order of operations like so:
-10÷3= -3.333...
l-3.333...l = 3.333... 
xz_007 [3.2K]3 years ago
6 0
By definition, the absolute value of a number is given by:
 | a | = a

 Where,
 The number a is a real number. This means that the value of a is both negative and positive.
 The result is always greater than zero.
 Therefore, the absolute value of the given numbers is given by:
 |9.8| = 9.8
 |-\frac{10}{3}| =  \frac{10}{3}
 Answer:
 
the absolute value of 9.8 and of -10/3 is:
 
|9.8| = 9.8
 |-\frac{10}{3}| = \frac{10}{3}
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Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt
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At the null hypothesis, it is <u>tested if it does not outlast by more than 2 hours</u>, that is, the subtraction is not more than 2:

H_0: \mu_B - mu_A \leq 2

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

H_1: \mu_B - \mu_A > 2

  • The sample means are: \mu_A = 8.65, \mu_B = 11.23
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Hence, the standard errors are:

s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934

The distribution of the difference has <u>mean and standard deviation</u> given by:

\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58

s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 2 is the value tested at the hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.58 - 2}{0.2735}

t = 2.12

The critical value for a <u>right-tailed test</u>, as we are testing if the subtraction is greater than a value, with a <u>0.05 significance level</u> and 12 + 12 - 2 = <u>22 df</u> is given by t^{\ast} = 1.71

Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

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