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Nimfa-mama [501]
3 years ago
7

Find the absolute value of 9.8 and of -10/3.

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0
The absolute value of 9.8 is 9.8. The absolute value of -10/3 is found by using your order of operations like so:
-10÷3= -3.333...
l-3.333...l = 3.333... 
xz_007 [3.2K]3 years ago
6 0
By definition, the absolute value of a number is given by:
 | a | = a

 Where,
 The number a is a real number. This means that the value of a is both negative and positive.
 The result is always greater than zero.
 Therefore, the absolute value of the given numbers is given by:
 |9.8| = 9.8
 |-\frac{10}{3}| =  \frac{10}{3}
 Answer:
 
the absolute value of 9.8 and of -10/3 is:
 
|9.8| = 9.8
 |-\frac{10}{3}| = \frac{10}{3}
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x+10>20  subtract 10 from both sides

x>10

or in interval notation, x=(10, +oo)
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Postulates can be used to prove theorems.<br><br> True<br><br> False
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Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A
alekssr [168]

Answer:

\theta_{CAB}=128.316

\theta_{ABC}=25.842

\theta_{BCA}=25.842

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}

AB= \sqrt{(-3-1)^2+(0-3)^2}=5

BC= \sqrt{(1-1)^2+(3-(-3))^2}=9

CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}

\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}

\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}

\theta_{CAB}=\arccos{-\dfrac{0.62}}

\theta_{CAB}=128.316

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}

\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)

\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)

\theta_{ABC}=\arcsin{0.4359}\right)

\theta_{ABC}=25.842

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

\theta_{BCA}=25.842

this can also be checked using the fact the sum of all angles inside a triangle is 180

\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180

25.842+128.316+25.842

180

6 0
3 years ago
Read 2 more answers
How do you simplify this
kramer

Answer:

multiply the bottom and the top by route 2 minus route 3

this gives 4 route 2 minus route 18 over minus 1

this gives minus 4 route 2 add route 18

route 18 simplifies to 3 route 2

minus 4 route 2 add 3 route 2 gives minus route 2 as the answer

3 0
2 years ago
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lara31 [8.8K]

Answer:

Acute angle, doesn't have a 90 degree angle to be a right triangle, neither a wide angle to be an obtuse triangle.

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