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Charra [1.4K]
3 years ago
10

How many days are in 56 years and show work take a pic or on type

Mathematics
2 answers:
gavmur [86]3 years ago
6 0
56*365=20440
56/4=14 (this is how many leap years are within 56 years)
20440+14=20454 days
Sveta_85 [38]3 years ago
3 0
365×56=20440
There are 20,440 days in 56 years
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There are 614,952 pepole living in a city round this number ot the nearest thousand
Dima020 [189]

Answer:

615,000

Step-by-step explanation:

When you "round to the nearest _____" regardless of what goes in the blank the steps are nearly always the same:

Identify which place value you are rounding to. The smaller the place value, the more accurate the final result will be.

Look to the next smallest place value, the digit to the right of the place value you're rounding to. For example, if you want to round to the nearest ten you'd look at the ones place.

If the digit in the next smallest place value is less than five (0, 1, 2, 3, or 4), you leave the digit you want to round to as-is. Any digits after that number (including the next smallest place value you just looked at) become zeros, or drop-off if they're located after the decimal point. This is called rounding down.

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3 0
3 years ago
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Use the figure below to determine the length of sides b and c. options: b = 5√3, c = 10 b =10, c = 5√3 b = 5√2, c = 10√3 b = 5,
Reil [10]

Answer:

A

Step-by-step explanation:

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The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is \left(\frac{-9}{2}, \frac{-3}{2}\right)

<u>Solution:</u>

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We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

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Answer:

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Step-by-step explanation:

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