Answer:
The histogram is right-skewed.
Step-by-step explanation:
The income of all households in the United States can be categorized as low, medium and high.
Not many people earn a high income. So the proportions of people decreases as the income increases.
Most of the people earn a medium income. So the mode of the data would be somewhere in the start of the the distribution.
There are many households that earn a low income. But this proportion is not more than the proportion of people earning low income.
So the histogram for income distribution will have a long right tail with maximum data at the starting point.
This implies that the histogram is right-skewed.
Answer:
x ≥ -1
Step-by-step explanation:
Hope this helps
Answer:
yes to both
Step-by-step explanation:
For a relationship to be a function then each value of x must relate to exactly one unique value of y.
This is the case in this table as
2 → 76
4 → 152
6 → 228
All unique values thus a function
To determine if it is linear then the rate of change is constant for each set of ordered pairs. This is measured using the slope formula.
m = 
with (x₁, y₁ ) = (2, 76) and (x₂, y₂ ) = (4, 152 ) ← ordered pair from table
m = 
= 
= 38
Repeat with (x₁, y₁ ) = (4, 152) and (x₂, y₂ ) = (6, 228)
m = 
= = 38
Since rate of change is constant then function is linear
Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
_____
<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
I hope this helps you
4/5-1/3
(4.3/5.3)-(1.5/3.5)
12/15-5/15
7/15
