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AlexFokin [52]
2 years ago
11

If log(16)=s, what is the value of 2/3 log(6400) - 1/3 log(1600) in terms of s?

Mathematics
1 answer:
eduard2 years ago
8 0

The value of   \dfrac{ 2}{3} log(6400) - \dfrac{1}{3} log(1600)  in terms of s will be

\dfrac{2}{3}(400s)-\dfrac{1}{3}(1000s)

<h3>What is Logrithm?</h3>

A quantity representing the power to which a fixed number (the base) must be raised to produce a given number.

Here we have the expression:-

\dfrac{ 2}{3} log(6400) - \dfrac{1}{3} log(1600)

So in terms of s the expression will become:-

\dfrac{2}{3}(400s)-\dfrac{1}{3}(1000s)

To know more about logarithm follow

brainly.com/question/25710806

#SPJ1

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