What is the solution to n/4 = -12.4?

Arisa [49]

$8x^2-7x-18=0\\\\ 8x^2-16x+9x-18=0\\\\8x(x-2)+9(x-2)=0\\\\(x-2)(8x+9)=0\ \ \ \Leftrightarrow\ \ \ (x-2=0\ \ \ or\ \ \ 8x+9=0)\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=- \frac{9}{8}$

7 0

4 years ago

Can someone pls help

Cloud [144]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Your client has saved $2500 for a down payment on a house. A government loan program requires a down payment equal to 2.5% of th

EleoNora [17]

Answer:

The largest amount that could be received is $100,000

Step-by-step explanation:

Here in this question , we are interested in calculating the largest amount loan amount that could be received.

Now, let the loan amount be $x

What we know is that the amount of down payment paid is 2.5% of the loan amount.

Thus, mathematically;

2.5% of x = 2500

2.5/100 * x = 2500

2.5x/100 = 2500

2.5x = 100 * 2500

x = (2500 * 100)/2.5

x = 100,000

The largest loan amount that could be received with the program is $100,000

8 0

4 years ago

Keith takes 12 hours to clean the store, and mike takes 10 hours to finish the job. how hong will they take together?

svlad2 [7]

Find the average value
12 hours + 10 hours = 22 hours
22 hours/2 = 11 hours
Together it will take Keith and Mike 11 hours to clean the store.

6 0

4 years ago

A recent study focused on the amount of money single men and women save monthly. The information is summarized here. Assume that

beks73 [17]

Answer:

$t=\frac{(23 -28)-(0)}{8.126\sqrt{\frac{1}{25}+\frac{1}{30}}}=-2.272$

$p_v =2*P(t_{53}$

If we compare the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis that the means are equal between the two groups at this significance level.

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2 \neq 0$

Our notation on this case :

$n_1 =25$ represent the sample size for men

$n_2 =30$ represent the sample size for women

$\bar X_1 =23$ represent the sample mean for men

$\bar X_2 =28$ represent the sample mean for the women

$\sigma_1=5$ represent the population standard deviation for men

$\sigma_2=10$ represent the population standard deviation for women

First we can begin finding the pooled variance:

$\S^2_p =\frac{(25-1)(5)^2 +(30 -1)(10)^2}{25 +30 -2}=66.038$

And the deviation would be just the square root of the variance:

$S_p=8.126$

And now we can calculate the statistic:

$t=\frac{(23 -28)-(0)}{8.126\sqrt{\frac{1}{25}+\frac{1}{30}}}=-2.272$

Now we can calculate the degrees of freedom given by:

$df=25+30-2=53$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{53}$

If we compare the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis that the means are equal between the two groups at this significance level.

3 0

4 years ago