Question

Write the standard form of the equation of the line trough the given point with the given slope.

Answer 1

Step-by-step explanation:

we use the point-slope approach :

y - y1 = m(x - x1)

m is the slope, and (x1, y1) is a point on the line.

so,

1.

y - 2 = 7(x - 1) = 7x - 7

y = 7x - 5

2.

y - -1 = -1×(x - 3) = -x + 3

y + 1 = -x + 3

y = -x + 2

3.

y - 5 = -4(x - -2) = -4x - 8 (3x a "-" is a "-" for 8)

y = -4x - 3

4.

y - 5 = 5/3 × (x - 3) = 5x/3 - 5

y = 5x/3 or 5/3 × x

Answer 2

Answer:

1. $7x-y=5$

2. $x+y=2$

3. $4x+y=-3$

4. $5x-3y=0$

Step-by-step explanation:

Since we already know the slope and the coordinates of one point, first use the point-slope form to create an equation.

$y-k=m(x-h)$

$y-2=7(x-1)$

$y-2=7x-7$

$7x-y=5$

$y+1=-1(x-3)$

$y+1=-x+3$

$x+y=2$

$y-5=-4(x+2)$

$y-5=-4x-8$

$4x+y=-3$

$y-5=\frac{5}{3} (x-3)$

$y-5=\frac{5}{3}x-5$

$3y-15=5x-15$

$5x-3y=0$