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Ksenya-84 [330]
2 years ago
6

Please Help ASAP!!!!!!

Mathematics
2 answers:
boyakko [2]2 years ago
7 0
The sides would be equal if that’s what we were looking at

-the correct answer itself would be A.) 4//correct me if I’m wrong but 3x-6 is dividing or multiplying into the smallest number then adding it on to the other number //2)x-3x •-6 =4

Hope this helps
Bumek [7]2 years ago
4 0

Answer: 6

The sides are equal.

Thus

3x-6=x+2\\2x=8\\x=4

$JP=x+2=4+2=\boxed{6}$

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A manufacturer makes three types of screws. Type A comes in a bulk pack of 1000 screws. Type B comes in a bulk pack of 500 screw
Tpy6a [65]

Answer:

Step-by-step explanation:

Given that a manufacturer makes three types of screws

Type             A        B           C Total

   

Pack         1000 500   800  

P for flaw 0.001 0.03 0.005  

Pack*p                 1 15                    4     20

a) Expected total number of defective screws = 20

b) For one pack each no of defective screws =20

Hence for 5 expected number number of packs form each should be 1/3

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3 years ago
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Step-by-step explanation:

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2 years ago
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boyakko [2]

Answer:

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Step-by-step explanation:

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3 years ago
CONVERTING METRIC UNITS - LENGTH WEIGHT & VOLUME 1
zzz [600]

Answer:

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Step-by-step explanation:

4 0
3 years ago
show that thw roots of the equation (x-a)(x_b)=k^2 are always real if a,b and k are real. Please I really need help with this
VLD [36.1K]

Answer:

see explanation

Step-by-step explanation:

Check the value of the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real

• If b² - 4ac = 0 roots are real and equal

• If b² - 4ac < 0 then roots are not real

given (x - a)(x - b) = k² ( expand factors )

x² - bx - ax - k² = 0 ( in standard form )

x² + x(- a - b) - k² = 0

with a = 1, b = (- a - b), c = -k²

b² - 4ac = (- a - b)² + 4k²

For a, b, k ∈ R then (- a - b)² ≥ 0 and 4k² ≥ 0

Hence roots of the equation are always real for a, b, k ∈ R


           

8 0
3 years ago
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