Question

Which equation represents a line that passes through (–9, –3) and has a slope of –6?

Answer 1

Answer:

y + 3 = -6(x + 9) - point-slope form

y = -6x - 57 - slope-intercept form

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

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We have the slope m = -6 and the point (-9, -3).

Substitute:

$y-(-3)=-6(x-(-9))\\\\y+3=-6(x+9)$

Convert to the slope-intercept form (y = mx + b):

$y+3=-6(x+9)$           use the distributive property

$y+3=-6x-54$         subtract 3 from both sides

$y=-6x-57$