You calculate the markup or markdown in absolute terms (you find by how much the quantity changed), and then you calculate the percent change relative to the original value. So they're really just another form of "increase - decrease" exercises.
Example:
A computer software retailer used a markup rate of 40%. Find the selling price of a computer game that cost the retailer $25.
The markup is 40% of the $25 cost, so the markup is:
(0.40)(25) = 10
Then the selling price, being the cost plus markup, is:
25 + 10 = 35
The item sold for $35.
Answer:
Step-by-step explanation:
1.25 yd x 2 yd x 1.5 yd
= 2.5 yd^2 x 1.5 yd
= 3 3/4 yd^3
answer is D
Assuming the top of the hill is 0.
Squirrel begins at 0 = 0
Squirrel runs down 23 feet = 0 - 23 = -23
Squirrel runs up 23 feet = -23 + 23 = 0
An integer that represents the squirrel's final position is 0.
Hope this helps!! :)
1. <span>Suppose that a single card is selected from a standard 52-card deck. what is the probability that the card drawn is a club ?
From the total 52 card, there is 13 club card. There is no scenario that need to be considered in this problem. The probability to draw club would be:
the number of club cards/</span>total number of cards <span>= 13/52= 1/4= 25%
2. </span><span>suppose that a single card is drawn from a standard 52-card deck, but it is told that the card is black. what is the probability that the card drawn is a <span>club ?
</span></span>
In this scenario, the card is already known as black. Out of 52 cards, there is 26 black card. Out of 26 black cards, there are 13 clubs cards. The probability to draw club would be:
the number of club cards/total number of black cards= 13/26= 1/2= 50%
Answer:
Step-by-step explanation:
The formula for determining the confidence interval for the difference of two population means is expressed as
Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)
Where
x1 = mean sale amount for mail order sales = 82.70
x2 = mean sale amount for internet sales = 66.9
s1 = sample standard deviation for mail order sales = 16.25
s2 = sample standard deviation for internet sales = 20.25
n1 = number of mail order sales = 17
n2 = number of internet sales = 10
For a 99% confidence interval, we would determine the z score from the t distribution table because the number of samples are small
Degree of freedom =
(n1 - 1) + (n2 - 1) = (17 - 1) + (10 - 1) = 25
z = 2.787
Margin of error =
z√(s²/n1 + s2²/n2) = 2.787√(16.25²/17 + 20.25²/10) = 20.956190
