The formula for aerobic respiration in animals can be shown by the equation below. A glucose molecule is broken down by enzymes in the presence of oxygen to make carbon dioxide, water, and ATPs. Carbon IV oxide is expelled by the lungs.
C₆H₁₂O₆ + 6O₂ --> 6CO₂ + 6H₂O + 38 ATP
This process occurs in two stages. Glycolysis (that does not require oxygen) occurs in the cytoplasm of cells. The products of the glucose breakdown in this stage is pyruvate, CO₂ and 2 net ATPs. The pyruvate is then converted to acetyl-CoA that enters the second stage called Citric/Krebs cycle. This second stage happens in the mitochondria. The products are CO₂, H₂O and 34 ATPs
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Answer:
The order must be K2→K1, since the permanently active K1 allele (K1a) is able to propagate the signal onward even when its upstream activator K2 is inactive (K2i). The reverse order would have resulted in a failure to signal (K1a→K2i), since the permanently active K1a kinase would be attempting to activate a dead K2i kinase.
Explanation:
- You characterize a double mutant cell that contains K2 with type I mutation and K1 with type II
mutation.
- You observe that the response is seen even when no extracellular signal is provided.
- In the normal pathway, i f K1 activat es K2, we expect t his combinat ion of two m utants to show no response with or without ext racell ular signal. This is because no matt er how active K1 i s, it would be unable to act ivate a mutant K2 that i s an activit y defi cient. If we reverse the order, K2 activating K1, the above observati on is valid. Therefore, in the normal signaling pathway, K2 activates K1.
Answer: afforestation
Explanation:by planting trees they would be able to "inhale "the carbon iv oxide and in exchange exhale Oxygen
