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3 years ago

For this figure what is the value of X? How did you solve this?

Mathematics

1 answer:

Ivanshal [37]3 years ago

6 0

Answer:

x=60

Step-by-step explanation:

This is a parallelogram.

For a parallelogram,

sum of angles in one side is 180.

we know, in a parallelogram,

the consecutive angles are supplementary or

their sum is 180.

So, we get,

x+33+87=180

or, x+120=180

subtracting 120

x+120-120=180-120

or, x=60

You might be interested in

Solve using square root method

avanturin [10]

$\frac{1}{2}(x+5)^2 + 9 = -15$

$\frac{(x+5)^2+18}{2} = \frac{-30}{2}$

Cancel out the denominators.

(x+5)² + 18 = -30

(x+5)² = -30 - 18

(x+5)² = -48

The equation is impossible, we have a negative number.

There isn't a number that squared gives a negative number (the square is always positive).

√(x+5)² = +/- √-48

x+5 = +/- √-48

IMPOSSIBLE

You can write the result in imaginary numbers

x+5=+/- 4i√3

6 0

2 years ago

What is the perimeter of a rhombus whose diagonals measure 42cm and 56cm?

Trava [24]

Answer:

676

Step-by-step explanation:

d1×d2/2

42×56/2

1352/2=676

please check it by doing again

3 0

2 years ago

Read 2 more answers

10 points if you solve this one problem.

zalisa [80]

Answer:

150

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

<1 + <2 = <3

3x+11 + 3x+19 = 7x+10

Combine like terms

6x+30 = 7x+10

Subtract 6x from each side

6x -6x+30 = 7x-6x+10

30 = x+10

Subtract 10 from each side

30-10 = x+10-10

20 =x

We need to find angle 3

<3 = 7x+10

= 7(20)+10

= 140+10

= 150

7 0

2 years ago

Help me plz I’ll give brainlist plz!!!!!!!!!!!

marishachu [46]

Answer:

answer is 10/3 thats the answer

5 0

2 years ago

The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-

Elena-2011 [213]

$y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

$(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)$

3 0

1 year ago