Answer: 12.
To solve this problem, let's first solve for x. Thi is easiest done by figuring what QR is in terms of x using two equations, both from different lines.
In the first line: QR = 15 - 4x.
In the third line:QR = 13x - 1 - x = 12x - 1.
Now, we have to set these equations equal to each other. 15 - 4x = 12x - 115 = 16x - 116x = 16x = 1
Next, we take line three, 13x - 1, and substitute x as 1. The answer is 12.
Answer:
perp. : 1/3= m
y + 8 = 1/3(x -4): answer is c
y + 24/3 = (1/3)x - 4/3
y = (1/3)x - 28/3
Step-by-step explanation:
answer is c
Scientific notation implies that all the zeros are taken away and replaced with a 10 raised to whatever appropriate power would be necessary to make the number in scientific notation equal to the original number.
In the number 780,000,000, we can see that there are 7 zeros, but the number before the zeros has two digits, so we need to tuck the decimal point in there, because the number has to be between 1 and 10 for math reasons.
7.8 ... but what do we raise it to? We know it has to be 10, but to what power? Well, we just count how many places to the left the decimal point has traveled. From the original number, the decimal point shifted 8 places to the left, so that is the number that we will raise the 10 to.
The final number looks like this:

780,000,000 in scientific notation is <span>

Hope that helped =)</span>
Answer:
97.3%
Step-by-step explanation:
Let the three bulbs be A, B and C respectively.
Let P(A) denote the probability that the first bulb will burn out
Let P(B) denote the probability that the second bulb will burn out
Let P(C) denote the probability that the third bulb will burn out
Now, we are told that Each one has a 30% probability of burning out within the month.
Thus;
P(A) = P(B) = P(C) = 30% = 0.3
Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;
P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))
P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%