All categories

3 years ago

Find an equation for a quartic function containing the following points: (2, 60), (-3, 0), (-1, 0), (4, 0), (1, 0).

Mathematics

2 answers:

olga nikolaevna [1]3 years ago

5 0

Answer:

Step-by-step explanation:

tia_tia [17]3 years ago

3 0

Answer:

f(x) = -2(x + 3)(x + 1)(x - 4)(x - 1) or

f(x) = -2x^4 + 2x^3 + 26x^2 - 2x -24.

Step-by-step explanation:

The zeros of the function are at (-3, 0), (-1, 0), (4, 0), (1, 0) so in factor form the function is:

a(x + 3)(x + 1)(x - 4)(x - 1) where a is some constant.

We find a by substituting the point (2, 60)

60 = a(2+3)(2+1)(2-4)(2-1)

-30a = 60

a = -2.

So the function is -2(x + 3)(x + 1)(x - 4)(x - 1) .

You might be interested in

Solve each equation for y. Then find the value of y for each value of x. y+3x=8;x=-2,0,2

damaskus [11]

Y=-3x+8
when x=-2:
y=-3(-2)+8
y=6+8
y=14
when x=0
y=-3(0)+8
y=0+8
y=8
when x=2
y=-3(2)+8
y=-6+8
y=2

6 0

3 years ago

Please help! Correct answer only, please! I need to finish this assgnment this week! Matrix P has a dimensions of 3 X 4 and Matr

Temka [501]

Answer: C

Step-by-step explanation:

Your answer is correct! When you multiply 2 matrices, the inner dimensions have to be equal. If they are equal, the resulting dimensions would be the outer dimentions.

(<u>3</u>×4)(4×<u>5</u>)

Since the inner (bolded) dimensions are the same, in this case 4×4, we know these matrices can be multiplied.

Since these matrices can be multiplied, the product will be 3×5, the underlined outer dimensions.

4 0

4 years ago

10 minus the product of 5 in the number G is more than 80

DENIUS [597]

Answer:

10-5g >80

Step-by-step explanation:

10-5g >80

This is the statment if u want it.

8 0

3 years ago

Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math

alex41 [277]

Answer: $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

Step-by-step explanation:

Given two upward facing parabolas with equations

$y=6x^2 & y=x^2+2$

The two intersect at

$6x^2=x^2+2$

$5x^2=2$

$x^2$ = $\frac{2}{5}$

x= $\pm \sqrt{\frac{2}{5}}$

area enclosed by them is given by

A= $\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx$

A= $\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx$

A= $4\left [ \sqrt{\frac{2}{5}} \right ]-\frac{5}{3}\left [ \left ( \frac{2}{5}\right )^\frac{3}{2}-\left ( -\frac{2}{5}\right )^\frac{3}{2} \right ]$

A= $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

7 0

3 years ago

Jake throws a dart that hits the square shown below:

mrs_skeptik [129]

21.5.......:::..............:.::.::..

7 0

3 years ago