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alexandr1967 [171]
3 years ago
10

Find an equation for a quartic function containing the following points: (2, 60), (-3, 0), (-1, 0), (4, 0), (1, 0).

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
5 0

Answer:

a

Step-by-step explanation:

tia_tia [17]3 years ago
3 0

Answer:

f(x) = -2(x + 3)(x + 1)(x - 4)(x - 1)  or

f(x) = -2x^4 + 2x^3 + 26x^2 - 2x  -24.

Step-by-step explanation:

The zeros of the function are  at (-3, 0), (-1, 0), (4, 0), (1, 0) so in factor form the function is:

a(x + 3)(x + 1)(x - 4)(x - 1)      where a is some constant.

We find a by substituting the point (2, 60)

60 = a(2+3)(2+1)(2-4)(2-1)

-30a = 60

a = -2.

So the function is -2(x + 3)(x + 1)(x - 4)(x - 1) .

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