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3 years ago

Find an equation for a quartic function containing the following points: (2, 60), (-3, 0), (-1, 0), (4, 0), (1, 0).

Mathematics

2 answers:

olga nikolaevna [1]3 years ago

5 0

Answer:

Step-by-step explanation:

tia_tia [17]3 years ago

3 0

Answer:

f(x) = -2(x + 3)(x + 1)(x - 4)(x - 1) or

f(x) = -2x^4 + 2x^3 + 26x^2 - 2x -24.

Step-by-step explanation:

The zeros of the function are at (-3, 0), (-1, 0), (4, 0), (1, 0) so in factor form the function is:

a(x + 3)(x + 1)(x - 4)(x - 1) where a is some constant.

We find a by substituting the point (2, 60)

60 = a(2+3)(2+1)(2-4)(2-1)

-30a = 60

a = -2.

So the function is -2(x + 3)(x + 1)(x - 4)(x - 1) .

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Mandarinka [93]

Answer:

In summation form $\sum_{n = 1} ^{5} 6(6)^{n - 1}$

Step-by-step explanation:

Within one hour, the first person gives a stack of flyers to six people and within the next hour, those six people give a stack of flyers to six new people.

So, in the first 5 hours, the summation of people that receive a stack of flyers not including the initial person will be given by

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3 years ago

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I already know the answer to this problem, I want a explanation on how to get the answer.

DochEvi [55]

$\\ \bull\tt\dashrightarrow BC=CE$

$\\ \bull\tt\dashrightarrow 3x+3y=7x+5y$

$\\ \bull\tt\dashrightarrow 7x-3x=3y-5y$

$\\ \bull\tt\dashrightarrow 4x=-2y$

$\\ \bull\tt\dashrightarrow 2x=-y$

$\\ \bull\tt\dashrightarrow \dfrac{x}{y}=\dfrac{-1}{2}$

Now

$\\ \bull\tt\dashrightarrow BE=BC+CE+CD$

$\\ \bull\tt\dashrightarrow BE=3x+3y+7x+5y+5x-2y+6$

$\\ \bull\tt\dashrightarrow BE=15x+6y+6$

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2 years ago

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andreyandreev [35.5K]

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dybincka [34]

Answer:

Step-by-step explanation:

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2 years ago

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vesna_86 [32]

Answer:

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Step-by-step explanation:

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