You can solve this with a proportion. If you know that 23 tagged alligators were in a 200 alligator sample, there are 90 tagged alligators in the entire river. Written otherwise:
23/200 = 90/x
and solve for x:
x = 782.608...
So the "best estimate" would be around 783 alligators. Hope that helps! If you liked this answer please rate it as brainliest!! thank you!!!
Y determines how many hours, and x gives you the whole amount.
Answer:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
Out of 100 people sampled, 42 had kids.
This means that 
99% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).
Answer:
Step-by-step explanation:
3 pieces such that each piece is 2 cm longer then the next...
x , x + 2, x + 4
x + x + 2 + x + 4 = 30
3x + 6 = 30
3x = 30 - 6
3x = 24
x = 24/3
x = 8
x + 2 = 8 + 2 = 10
x + 4 = 8 + 4 = 12
check...
8 + 10 + 12 = 30
18 + 12 = 30
30 = 30 (correct)...it checks out
the ribbon lengths are : 8 cm, 10 cm, and 12 cm
