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mojhsa [17]
3 years ago
9

Calisto Publishing Co. sells graphic novels and comics to a large retailer for $7.50 per book,

Mathematics
1 answer:
Grace [21]3 years ago
3 0

Answer:

life suck and night night

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The distance traveled by a falling object, d(t),seconds is described by this function
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The Answer is B. 14.7 meters per second
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Which represents the inverse of the function f(x)=4x​
Galina-37 [17]
F-1(x)=x/4 represents the inverse function because to find the inverse you have to interchange the variables & solve for y
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3 years ago
Which expression is equivalent to 5a+20? A: 5(5a+4). B: 5(a+4). C: 5(a+20). D: 5(a+1)
guajiro [1.7K]

Answer:

5(a+4)

Step-by-step explanation:

expression is equivalent to 5a+20

To get the equivalent expression we need to factor the given expression

5a+ 20

5a can be written as 5 * a

20 can be written as 5*2*2

WE can see that common factor is 5 for both 5a and 20

So GCF is 5

Now we factor out GCF 5

WE put 5 outside and write all the left of factors inside the parenthesis

5a +20

5 (a+2*2)

5(a+4)

4 0
3 years ago
Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not
IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=4,\ hypotenuse=10

Substitute:

4^2+leg^2=10^2

16+leg^2=100             <em>subtract 16 from both sides</em>

leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}

sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}

Substitute:

hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}

\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}

5 0
3 years ago
I NEED HELP!!!!<br> what is the solution for x=4?
umka2103 [35]

Answer:

its basically just x=4

Step-by-step explanation:

8 0
2 years ago
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