Dont press on the link, its. asc
I. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point.
So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL
ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the steps
Answer:
d^-1(t)=t/70
Step-by-step explanation:
<span>'x' can be anything. There's no information here to say that it must be
one thing or another. You can't find 'x', because there is no
equation.
You can probably simplify the fraction by doing some factoring, but
there's
no way to tell a value for 'x'. As long as 'x' is not -4, it can be anything, and
its value determines the value of the fraction.</span>
It looks like you have
Substituting these in to the plane equation, we have
When 
, we get the point
