No, because Bernie had to run 9 meters 7.77777778 time (70/9) and each of those 9-meter sections took 4 seconds, so her time was 31.1111111 (7.77777778*4). While Wendel had to run 61 meters 70-his headstart (9 meters) (70-9). So he only had to run 30.5 blocks of 2 meters (61/2). And since they're only 1 second long, it's 30.5*1=30.5. The answer then is NO because (Bernie) 31.1111111 seconds > 30.5 seconds (Wendel).
Answer:
<em>The train must travel at 50 km/hr to make it on time.</em>
<em></em>
Step-by-step explanation:
distance to be covered = 55 km
time to cover this distance = 1 hr 20 min
1 hr 20 min = 1.33 hrs (20 min = 20/60 hrs = 0.33 hrs)
The train travels the first 30 km distance at a speed of 36 km/hr
and we know that time taken = distance/speed
therefore the time taken to run this 30 km will be
time = 30/36 = 0.83 hr
The train still has 55 - 30 = 25 km to cover,
and the time left is 1.33 - 0.83 = 0.5 hrs left
to make it on time, the train must travel at
speed = distance/time = 25/0.5 = <em>50 km/hr</em>
Answer:
6.2
Step-by-step explanation:
Actual value: 6.15636257
Answer:
Hello! What are you trying to ask?
Step-by-step explanation:
Solution: (-Infinite, -8/3] U (4, Infinite)
Using that a fraction is greater than or equal to zero when the numerator and denominator have the same sign:
a/b>=0. Then we have two cases:
Case 1) If the numerator is positive, the denominator must be positive too (at the same time):
if a>=0 ∩ b>0
Or (U)
Case 2) If the numerator is negative, the denominator must be negative too (at the same time):
if a<=0 ∩ b<0
In this case a=3x+8 and b=x-4, then:
Case 1):
if 3x+8>=0 ∩ x-4>0
Solving for x:
3x+8-8>=0-8 ∩ x-4+4>0+4
3x>=-8 ∩ x>4
3x/3>=-8/3 ∩ x>4
x>=-8/3 ∩ x>4
Solution Case 1: x>4 = (4, Infinite)
Case 2):
if 3x+8<=0 ∩ x-4<0
Solving for x:
3x+8-8<=0-8 ∩ x-4+4<0+4
3x<=-8 ∩ x<4
3x/3<=-8/3 ∩ x<4
x<=-8/3 ∩ x<4
Solution Case 2: x<=-8/3 = (-Infinite, -8/3]
Solution= Solution Case 1 U Solution Case 2
Solution = (4, Infinite) U (-Infinite, -8/3]
Solution: (-Infinite, -8/3] U (4, Infinite)
